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Kisachek [45]
3 years ago
10

Isotonic compound have high melting point. Why ? Name the ions present in CaS.

Chemistry
1 answer:
yuradex [85]3 years ago
3 0

Explanation:

Because a large amount of energy is required to break the strong inter-ionic attraction.

CaS => Ca2+ & S2-

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What is the molarity of a solution that contains 125 g nacl in 4.00 l solution?
bogdanovich [222]

Answer:

[NaCl[ = 0.535M

Explanation:

We determine the moles of solute:

125 g . 1 mol/ 58.45 g = 2.14 moles

Molarity (mol/L) → 2.14 mol / 4L → 0.535M

Molarity is a sort of concentration that indicates the moles of solute in 1L of solution

4 0
3 years ago
What is created when an acid is mixed with a base?
Arturiano [62]

Answer:

If you mix equal amounts of a strong acid and a strong base, the two chemicals essentially cancel each other out and produce a salt and water. Mixing equal amounts of a strong acid with a strong base also produces a neutral pH (pH = 7) solution.

8 0
3 years ago
NH4NO3, whose heat of solution is 25.7 kJ/mol, is one substance that can be used in cold pack. If the goal is to decrease the te
makvit [3.9K]

Answer:

There are necessaries 35,2g of NH₄NO₃ per 100,0g of water to decrease the temperature of the solution from 25,0°C to 5,0°C

Explanation:

To decrease the temperature of the solution there are necessaries:

4,184J/g°C×(5,0°C-25,0°C)×(100,0g+X) = -Y

8368J + 83,68J/gX = Y <em>(1)</em>

Where x are grams of NH₄NO₃ you need to add and Y is the energy that you need to decrease the heat.

Also, the energy Y will be:

Y = 25700J/mol×\frac{1mol}{80,043g}X

Y = 321J/g X <em>(2)</em>

Replacing (2) in (1)

8368J + 83,68J/g X = 321J/g X

8363J = 237,32J/gX

<em>X = 35,2g</em>

<em />

Thus, there are necessaries 35,2g of NH₄NO₃ per 100,0g of water to decrease the temperature of the solution from 25,0°C to 5,0°C

I hope it helps!

6 0
3 years ago
Which tool is most suitable for a chemist to measure the mass of a liquid
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Chemists use beakers, flasks, burets and pipets to measure the volume of liquids. Plz mark as brainliest

7 0
3 years ago
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What is the formula of the chromium(iii) complex that contains two ammonia and four thiocyanate (scn−) ligands?
Nonamiya [84]
Answer is: formula of the complex is [Cr(NH₃)₂(SCN)₄<span>]</span>⁻<span>.
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+3 + 2</span>·0 + 4·(-1) = -1.
4 0
3 years ago
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