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love history [14]
3 years ago
9

Determine the number of ch2cl2 molecules in 25.0 g ch2cl2.determine the number of ch2cl2 molecules in 25.0 g ch2cl2.

Chemistry
2 answers:
Angelina_Jolie [31]3 years ago
6 0
Answer is: there is 1,77·10²³ molecules of CH₂Cl₂.
m(CH₂Cl₂) = 25 g.
n(CH₂Cl₂) = m(CH₂Cl₂) ÷ M(CH₂Cl₂).
n(CH₂Cl₂) = 25 g ÷ 85 g/mol.
n(CH₂Cl₂) = 0,294 mol.
N(CH₂Cl₂) = n(CH₂Cl₂) · Na.
N(CH₂Cl₂) = 0,294 mol · 6,023 1/mol.
N(CH₂Cl₂) = 1,77·10²³.
n - amount of substance.
Na - Avogadro number.
stepladder [879]3 years ago
4 0

Answer : The number of molecules of CH_2Cl_2 are, 1.77\times10^{23}

Explanation : Given,

Mass of CH_2Cl_2 = 25 g

Molar mass of CH_2Cl_2 = 85 g/mole

First we have to calculate the moles of CH_2Cl_2.

\text{Moles of }CH_2Cl_2=\frac{\text{Mass of }CH_2Cl_2}{\text{Molar mass of }CH_2Cl_2}=\frac{25g}{85g/mole}=0.294moles

Now we have to calculate the number of molecules of CH_2Cl_2.

As, 1 mole of CH_2Cl_2 contains 6.022\times 10^{23} number of molecules of CH_2Cl_2

So, 0.294 mole of CH_2Cl_2 contains 0.294\times 6.022\times 10^{23}=1.77\times10^{23} number of molecules of CH_2Cl_2

Therefore, the number of molecules of CH_2Cl_2 are, 1.77\times10^{23}

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