Answer:
2726.85 °C
Explanation:
Given data:
Initial pressure = 565 torr
Initial temperature = 27°C
Final temperature = ?
Final pressure = 5650 torr
Solution:
Initial temperature = 27°C (27+273 = 300 K)
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
T₂ = P₂T₁ /P₁
T₂ = 5650 torr × 300 K / 565 torr
T₂ = 1695000 torr. K /565 torr
T₂
= 3000 K
Kelvin to degree Celsius:
3000 K - 273.15 = 2726.85 °C
C. A nearly identical image.
Answer:
The final pressure of the gas is 0.915atm
Explanation:
We have to apply the Charles Gay Lussac Law, where the pressure changes directly proportional to absolute T°
- No change in volume
- The same moles in both situations
P1 / T1 = P2 / T2
0.991 atm / 342K = P2 / 316k
(0.991 atm / 342K) . 316K = P2
0.915 atm = P2
