1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
larisa86 [58]
3 years ago
6

A base is a substance that can_____ a hydroxide ion A) Bond with B) Accept C) Donate

Physics
1 answer:
kirill [66]3 years ago
4 0
A) bond with a hydroxide ion
You might be interested in
Please help me i em doing a test
Aleks [24]

Answer:

Student 2 protons and valence electrons

8 0
3 years ago
Read 2 more answers
Wat is the meaning of inference?
VladimirAG [237]

The meaning of inference is the process of inferring  something and it is a noun


5 0
4 years ago
Read 2 more answers
magine an astronaut on an extrasolar planet, standing on a sheer cliff 50.0 m high. She is so happy to be on a different planet,
Mama L [17]

Answer:

\Delta t=(\frac{20}{g'}+\sqrt{\frac{400}{g'^2}+\frac{100}{g'}  }  )-(\frac{20}{g}+\sqrt{\frac{400}{g^2}+\frac{100}{g}  }  )

Explanation:

Given:

height above which the rock is thrown up, \Delta h=50\ m

initial velocity of projection, u=20\ m.s^{-1}

let the gravity on the other planet be g'

The time taken by the rock to reach the top height on the exoplanet:

v=u+g'.t'

where:

v= final velocity at the top height = 0 m.s^{-1}

0=20-g'.t' (-ve sign to indicate that acceleration acts opposite to the velocity)

t'=\frac{20}{g'}\ s

The time taken by the rock to reach the top height on the earth:

v=u+g.t

0=20-g.t

t=\frac{20}{g} \ s

Height reached by the rock above the point of throwing on the exoplanet:

v^2=u^2+2g'.h'

where:

v= final velocity at the top height = 0 m.s^{-1}

0^2=20^2-2\times g'.h'

h'=\frac{200}{g'}\ m

Height reached by the rock above the point of throwing on the earth:

v^2=u^2+2g.h

0^2=20^2-2g.h

h=\frac{200}{g}\ m

The time taken by the rock to fall from the highest point to the ground on the exoplanet:

(50+h')=u.t_f'+\frac{1}{2} g'.t_f'^2 (during falling it falls below the cliff)

here:

u= initial velocity= 0 m.s^{-1}

\frac{200}{g'}+50 =0+\frac{1}{2} g'.t_f'^2

t_f'^2=\frac{400}{g'^2}+\frac{100}{g'}

t_f'=\sqrt{\frac{400}{g'^2}+\frac{100}{g'}  }

Similarly on earth:

t_f=\sqrt{\frac{400}{g^2}+\frac{100}{g}  }

Now the required time difference:

\Delta t=(t'+t_f')-(t+t_f)

\Delta t=(\frac{20}{g'}+\sqrt{\frac{400}{g'^2}+\frac{100}{g'}  }  )-(\frac{20}{g}+\sqrt{\frac{400}{g^2}+\frac{100}{g}  }  )

3 0
3 years ago
HELP RIGHT NOW THE RIGHT ANSWER GETS BRAINLEST!!!
cupoosta [38]
Solar Flares: C
Prominences: A
Sun Spots: D
Convection: B
3 0
3 years ago
Read 2 more answers
friction between the tire of a moving car and the dry pavement is: A. static B. rolling C. sliding D. riding
qwelly [4]

Answer:A static

Explanation:

6 0
3 years ago
Other questions:
  • Express fx and fy in terms of the length of the vector f and the angle θ in paired form
    13·1 answer
  • How does Newton's three laws of motion apply to the egg drop project
    6·2 answers
  • An is a heterogeneous mixture in which visible particles settle
    9·1 answer
  • A ____ agrees to help an immigrant become a citizen
    10·2 answers
  • A car weighing 15,000 n is speeding down the highway at 90 km/h. what is its momentum?
    11·2 answers
  • What two aspects of a force do scientists measure?
    15·1 answer
  • 1. The photon energy for light of wavelength 500 nm is approximately (Show your work).
    9·1 answer
  • a body starts from rest and accelerates uniformly at 5ms‐2. Calculate the time taken by the body to cover a distance of 1km​
    11·2 answers
  • How do you find the weight of an object when given the mass and acceleration?
    11·1 answer
  • The equatorial diameter of venus is 7,523 miles. if a mile equals 1.609 km, what is venus's diameter in kilometers?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!