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OlgaM077 [116]
3 years ago
13

Describle the path that moisture takes from the ocean to the runoff that forms a river

Physics
1 answer:
Sergeu [11.5K]3 years ago
3 0
<span>The path that moisture takes from the ocean to the runoff that forms a river is: 
</span>1.Evaporation (<span>water changes from a liquid to a gas or vapor)</span>
<span>2. Condensation (clouds are formed)
3. Precipitation (</span>Any form of water that falls to the Earth's surface from the clouds)
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How does Coulomb's law relate to test charges?
Feliz [49]
Coulomb's law applies to all charges.  It doesn't care what the specific
purpose of the individual charge may be at the moment.
7 0
4 years ago
A railway car having a total mass of 5.8 × 105 kg, moving with a speed of 9.1 km/h, strikes another car that has a mass of 8.7 ×
Jobisdone [24]

Answer:

Final speed of both the cars, V = 3.28 km/h

Explanation:

It is given that,

Mass of the railway car, m_1=5.8\times 10^5\ kg

Initial speed of the railway car, u_1=9.1\ km/h=2.52\ m/s

Mass of another car, m_2=8.7\times 10^5\ kg

Initial speed of another car, u_2=0

To find,

The speed of the coupled cars after the collision.

Solution,

It is a case of inelastic collision in which the linear momentum before and after the collision remains same. Let V is the coupled velocity of both of the cars. So,

m_1u_1+m_2u_2=(m_1+m_2)V

V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

V=\dfrac{m_1u_1}{(m_1+m_2)}

V=\dfrac{5.8\times 10^5\times 2.52778}{(5.8\times 10^5+8.7\times 10^5)}

V = 1.011 m/s

or

V = 3.28 km/h

So, the speed of the coupled cars after the collision is 3.28 km/h. Hence, this is the required solution.

3 0
3 years ago
Who was this scientist, what ideas did he form, and how did he figure out these new ideas of atoms?
saul85 [17]

Answer:

Atoms cannot be divided.

Explanation:

5 0
3 years ago
Can someone please help me ​
siniylev [52]

Answer:

M a = (M1 + M2) a = F         Newton's Second Law

F = (M2 - M1) g         net force on the system

a = (M2 - M1) / (M1 + M2) g

a = (9 - 7) / (9 + 7) g = 2 / 16 * 10.0 m/s^2 = 1.25 m/s^2

6 0
2 years ago
What is the speed of a 200-kilogram car that is driving with 2000 joules of kinetic energy? (SHOW ALL WORK)
Katyanochek1 [597]

Answer:

v ≈ 4.47

Explanation:

The Formula needed = <u>KE = </u>\frac{1}{2}<u> m v²</u>

<u></u>

Substitute with numbers known:

2000J = \frac{1}{2} × 200kg × v²

Simplify:

÷100       ÷100      (Divide by 100 on both sides)

2000J = 100 × v²

\frac{2000J}{100} =  v²

20 = v²

√         √             (Square root on both sides)

√20 = √v²

4.472135955 = v (Round to whatever the question asks)

v ≈ 4.47       (I rounded to 2 decimal places or 3 significant figures, as that is what it usually is)

3 0
3 years ago
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