Coulomb's law applies to all charges. It doesn't care what the specific
purpose of the individual charge may be at the moment.
Answer:
Final speed of both the cars, V = 3.28 km/h
Explanation:
It is given that,
Mass of the railway car, 
Initial speed of the railway car, 
Mass of another car, 
Initial speed of another car, 
To find,
The speed of the coupled cars after the collision.
Solution,
It is a case of inelastic collision in which the linear momentum before and after the collision remains same. Let V is the coupled velocity of both of the cars. So,




V = 1.011 m/s
or
V = 3.28 km/h
So, the speed of the coupled cars after the collision is 3.28 km/h. Hence, this is the required solution.
Answer:
M a = (M1 + M2) a = F Newton's Second Law
F = (M2 - M1) g net force on the system
a = (M2 - M1) / (M1 + M2) g
a = (9 - 7) / (9 + 7) g = 2 / 16 * 10.0 m/s^2 = 1.25 m/s^2
Answer:
v ≈ 4.47
Explanation:
The Formula needed = <u>KE = </u>
<u> m v²</u>
<u></u>
Substitute with numbers known:
2000J =
× 200kg × v²
Simplify:
÷100 ÷100 (Divide by 100 on both sides)
2000J = 100 × v²
= v²
20 = v²
√ √ (Square root on both sides)
√20 = √v²
4.472135955 = v (Round to whatever the question asks)
v ≈ 4.47 (I rounded to 2 decimal places or 3 significant figures, as that is what it usually is)