Answer:
120 moles of Mg
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
3Mg + 2H₃PO₄ —> Mg₃(PO₄)₂ + 3H₂
From the balanced equation above,
3 moles of Mg reacted to produce 3 moles of H₂.
Finally, we shall determine the number of mole of Mg needed to produce 120 moles of H₂. This can be obtained as follow:
From the balanced equation above,
3 moles of Mg reacted to produce 3 moles of H₂.
Therefore, 120 moles of Mg will also react to produce 120 moles of H₂.
Thus, 120 moles of Mg is needed for the reaction.
when an atom gains or loses an electron, it becomes an ion. Ions formed by the loss of an electron have a positive charge, and those formed by gaining an electron have a negative charge. Positive ions are called cations, and negative ions are called anions.
B, Because the classroom started with cylinder cups they should add 7mL into the cup and then transfer the 7mL on the cups
Answer:
Acids that form a complex with aluminum ions can eat their way through the oxide coating, however, so concentrated hydrochloric acid can dissolve aluminum. Zinc is also very reactive and lacks the passivating layer found on aluminum, so it reduces hydrogen ions from acids like hydrochloric acid to form hydrogen gas.
When we convert the given mass in grams and volume in liters to m/v percent, we recall that m/v percent is expressed as grams/100 milliliters. In this case the expression becomes (50 grams/ 2500 L)*(0.1L/100ml), that is equal to 0.002 grams/ 100 mL. Hence the the concentration is equal to 0.2 m/v percent.
