A ________ has wavy or wrinkled foliations. These rocks usually have a pseudo-metallic luster from the abundance of mica.
1 answer:
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Answer : The mass of aluminium (Al) is 0.413 g
Solution : Given,
Volume of at STP = 513 ml = 0.513 L ( 1 L = 1000 ml )
Molar mass of aluminium = 26.98 g/mole
First we have to calculate the moles of .
At STP,
1 mole occupies 22.4 L volume
now, 0.513 L gives moles of
The moles of = 0.0229 moles
The Net balanced chemical reaction is,
From the balanced chemical reaction, we conclude that
2 moles of Aluminium (Al) produces 3 moles of hydrogen gas
Now the number of moles of aluminium required in 0.0229 moles of hydrogen gas = = 0.0153 moles
Now we have to calculate the mass of aluminium.
Mass of aluminium = number of moles × Molar mass = 0.0153 moles × 26.98 g/mole = 0.413 g
The mass of aluminium required is 0.413 g.
Answer:
<h3>The answer is 286.36 cm³</h3>Explanation:
In order to find the volume be at 101.3 kPa we use Boyle's law which is
where
P1 is the initial pressure
P2 is the final pressure
V1 is the initial volume
V2 is the final volume
Since we are finding the final volume
From the question
P1 = 112 kPa = 112000 Pa
V1 = 259 cm³
P2 = 101.3 kPa = 101300 Pa
We have
We have the final answer as
<h3>286.36 cm³</h3>Hope this helps you