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BabaBlast [244]
2 years ago
10

A ________ has wavy or wrinkled foliations. These rocks usually have a pseudo-metallic luster from the abundance of mica.

Chemistry
1 answer:
zhuklara [117]2 years ago
7 0
The answer is B hope it helps pls mark branliest
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Write the correct IUPAC name for each of the following structures (3 marks per
a_sh-v [17]

Answer:

Methyl group

Explanation:

From the diagram shown, we can see that the family group CH3 is attached to the structure.

This is simply called a methyl group because it is derived from me than and written that way to show the direct bonding between carbon and the 3 hydrogen atoms.

3 0
2 years ago
Is it possible for an object not to be in motion and still have force acting upon it?
RSB [31]
Yes,this is an example:
An apple is sitting on a desk he is not in motion but one of the forces acting upon it is gravitational pull because is not floating around, the earth gravitational pull is pulling it down to the earth's surface.

3 0
3 years ago
In the drawing above, the hammer is acting as what type of simple machine? A. pulley B. screw C. wheel and axle D. lever
Mars2501 [29]
The drawing above is acting as a B) a screw.

4 0
2 years ago
Why does the octet rule not always refer to a stable arrangement of eight valence electrons
bearhunter [10]

Answer:

Explanation:

The octet rule does not always refer to a stable arrangement of eight valence electrons because there are some element that do not have eight valence electrons yet they are stable. for example;

i) Helium, It has two valence electrons and it is a stable gas.

ii) Boron triflouride (BF3); it has  six valence electrons (deficit valence electron) yet it is also stable.

iii) Phosphorus pentachloride (PCl5); it has more than eight valence electron and it is also stable.

For these few reasons it is not always advisable to say octet arrangement refer to stable eight valence electrons.  

4 0
3 years ago
How many grams of NH3 can be produced from 2.30 mol of N2 and excess H2.
MrRa [10]
<h3>Answer:</h3>

78.34 g

<h3>Explanation:</h3>

From the question we are given;

Moles of Nitrogen gas as 2.3 moles

we are required to calculate the mass of NH₃ that may be reproduced.

<h3>Step 1: Writing the balanced equation for the reaction </h3>

The Balanced equation for the reaction is;

   N₂(g) + 3H₂(g) → 2NH₃(g)

<h3>Step 2: Calculating the number of moles of NH₃</h3>

From the equation 1 mole of nitrogen gas reacts to produce 2 moles of NH₃

Therefore, the mole ratio of N₂ to NH₃ is 1 : 2

Thus, Moles of NH₃ = Moles of N₂ × 2

                                  = 2.3 moles × 2

                                  = 4.6 moles

<h3>Step 3: Calculating the mass of ammonia produced </h3>

Mass = Moles × molar mass

Molar mass of ammonia gas = 17.031 g/mol

Therefore;

Mass = 4.6 moles × 17.031 g/mol

         = 78.3426 g

         = 78.34 g

Thus, the mass of NH₃ produced is 78.34 g

3 0
3 years ago
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