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BabaBlast [244]
3 years ago
10

A ________ has wavy or wrinkled foliations. These rocks usually have a pseudo-metallic luster from the abundance of mica.

Chemistry
1 answer:
zhuklara [117]3 years ago
7 0
The answer is B hope it helps pls mark branliest
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An organic compound has one or more __________ atoms as part of the molescules structure.
Arte-miy333 [17]
I think it should be Carbon, because no organic compound exist without carbon.
5 0
4 years ago
Which of the following best illustrates the law of corkervation of energy?
Papessa [141]

Answer:

A . The work done stretching a spring is transformed into stored energy in the spring

Explanation:

The work done stretching a spring is transformed into stored energy in the spring is clear indication of the law of conservation of energy.

The law of conservation of energy states that "energy is neither created nor destroyed but transformed from one form to another".

  • In this problem, mechanical energy is used to stretch the spring.
  • The mechanical energy is converted to stored potential energy.

This is an energy transformation process.

3 0
3 years ago
When aluminum is placed in concentrated hydrochloric acid, hydrogen gas is produced.
KatRina [158]

Answer : The mass of aluminium (Al) is 0.413 g

Solution : Given,

Volume of H_{2}(g) at STP = 513 ml = 0.513 L           ( 1 L = 1000 ml )

Molar mass of aluminium = 26.98 g/mole

First we have to calculate the moles of H_{2}(g).

At STP,    

1 mole occupies 22.4 L volume

now, 0.513 L gives \frac{1mole\times0.513L}{22.4L} moles of H_{2}(g)

The moles of H_{2}(g) = 0.0229 moles

The Net balanced chemical reaction is,

2Al(s)+6HCl(aq)\rightarrow 2AlCl_3(aq)+3H_2(g)

From the balanced chemical reaction, we conclude that

2 moles of Aluminium (Al) produces 3 moles of hydrogen gas

Now the number of moles of aluminium required in 0.0229 moles of hydrogen gas = \frac{2moles\times 0.0229moles}{3moles} = 0.0153 moles

Now we have to calculate the mass of aluminium.

Mass of aluminium = number of moles × Molar mass = 0.0153 moles × 26.98 g/mole = 0.413 g

The mass of aluminium required is 0.413 g.

7 0
3 years ago
If the volume of oxygen gas is 259 cm3 at 112 kPa, what would the volume be at 101.3 kPa?
NARA [144]

Answer:

<h3>The answer is 286.36 cm³</h3>

Explanation:

In order to find the volume be at 101.3 kPa we use Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question

P1 = 112 kPa = 112000 Pa

V1 = 259 cm³

P2 = 101.3 kPa = 101300 Pa

We have

V_2 =  \frac{112000 \times 259}{101300}  =  \frac{29008000}{101300}  \\  = 286.3573543...

We have the final answer as

<h3>286.36 cm³</h3>

Hope this helps you

6 0
3 years ago
1 A pump with an 80% efficiency drives water up between two reservoirs through a piping system of total length L = 15 and circul
LenKa [72]
The correct answer to this question is that the length of 14 is it’s half Which would be 7
6 0
2 years ago
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