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german
3 years ago
12

How can I calculate the mass percent of carbon, nitrogen and oxygen in acetamide, C2H5NO?

Chemistry
1 answer:
Arte-miy333 [17]3 years ago
6 0

Partial mass of C, 12*2 = 24

Partial mass of H, 1*5 = 5

Partial mass of N, 14

Partial mass of O, 16

Now, total molar mass would be 24+5+14+16 = 59

mass % of carbon = 24 * 100 / 59 = 40.67%


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Define Malleability.<br>Ty!!<br>​
Aleonysh [2.5K]

Answer:

Malleability is a capability of making shaped or extended by hammering.

For example:

making a a ring of gold by hammering and heating gold.

6 0
3 years ago
How many milliliters of water will be created from a combustion reaction with 9.32×10 22nd power of ethanol molecules. Assume de
PolarNik [594]

Answer:

8.38 mL

Explanation:

1- The combustion reaction of ethanol (C2H5OH) in the presence of oxygen (O2) has as reaction products carbon dioxide (CO2) and water (H2O), the equation equaled is:

<em>C2H5OH (l) + 3 O2 (g) CO2 2 CO2 (g) + 3 H2O (l) </em>

2- By establishing the stoichiometric relationship between ethanol and water, you can calculate the number of molecules that will be created from the initial amount of alcohol molecules:

6,022x10 23 molecules of C2H5OH (1 mol) ___ 3 x 6,022x10 23 molecules of H2O (3 moles)

9.32x10 22 C2H5OH molecules _____ X = 2.80x10 23 H2O molecules

<em>Calculation: </em>

9.32x10 22 x (3 x 6.022x10 23) / 6.022x10 23 = 2.80x10 23 H2O molecules

3- Once the number of water molecules formed is obtained, with the molar mass the mass can be determined:

6.022x10 23 H2O molecules _____ 18.02 g

2.80x10 23 molecules of H2O _____ X = 8.38 g of H2O

<em>Calculation: </em>

2.80x10 23 x 18.02 g / 6.022x1023 = 8.38 g of H2O

4- Finally, having the density of water, you can calculate the volume that formed:

d = m / V  --> V = m / d

V = 8.38 g / 1.00 mL = 8.38 mL

The answer is that 8.38 mL of water is formed

5 0
3 years ago
Why do the deprotonated organic acid (RCO2-) and protonated organic base (RNH3+) go into the aqueous layer?
rodikova [14]

Answer:

The deprotonated organic acid (RCO2-) and protonated organic base (RNH3+) go into the aqueous layer because Organic compounds that are neither acids or bases do not react with either NaOH or HCl and, therefore remain more soluble in the organic solvent and are not extracted.

Explanation:

4 0
3 years ago
Upon combustion, a 0.8009 g sample of a compound containing only carbon, hydrogen, and oxygen produces 1.6004 g CO2 and 0.6551 g
Ede4ka [16]

Answer:

C2H4O

Explanation:

We can get the answer through calculations as follows.

From the mass of carbon iv oxide produced, we can get the number of moles of carbon produced. We first divide the mass by the molar mass of carbon iv oxide. The molar mass of carbon iv oxide is 44g/mol

The number of moles of carbon iv oxide is 1.6004/44 = 0.0364

Since there is only one carbon atom in CO2, the number of moles of carbon is same as above

The mass of carbon in the compound is simply the number of moles multiplied by the atomic mass unit. The atomic mass unit of carbon is 12. The mass of carbon in the compound is thus 12 * 0.0364= 0.4368g

From the number of moles of water, we can get the number of moles of hydrogen. To get the number of moles of water, we need to divide the mass of water by its molar mass. Its molar mass is 18g/mol. The number of moles here is thus 0.6551/18 = 0.0364 mole

But there are 2 atoms of hydrogen in 1 mole of water and thus, the number of moles of hydrogen is 2 * 0.0364= 0.0728

The mass of hydrogen is thus 0.0728* 1 = 0.0728g

The mass of oxygen equals the mass of the compound minus that of hydrogen and that of carbon.

= 0.8009 - 0.0728 - 0.4368 = 0.2913 mole

The number of moles of oxygen is the mass of oxygen divided by its atomic mass unit.

That equals 0.2913/16 = 0.0182 mole

The empirical formula can be obtained by dividing the number of moles of each by the smallest which is that of carbon and oxygen 0.0182

H = 0.0728/0.0182 = 4

C= 0.0364/0.0182 = 2

O= 0.0182/0.0182= 1

The empirical formula is thus C2H4O

3 0
3 years ago
Did democritus belive atoms retain there identity as a chemical reaction
mihalych1998 [28]
No He believed tiny particles were invisible and couldn't be changed....So No The person that believed in this was Dalton .
4 0
3 years ago
Read 2 more answers
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