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3 years ago

How can I calculate the mass percent of carbon, nitrogen and oxygen in acetamide, C2H5NO?

Chemistry

1 answer:

Arte-miy333 [17]3 years ago

6 0

Partial mass of C, 12*2 = 24

Partial mass of H, 1*5 = 5

Partial mass of N, 14

Partial mass of O, 16

Now, total molar mass would be 24+5+14+16 = 59

mass % of carbon = 24 * 100 / 59 = 40.67%

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How many moles are in 3.57 x 10 32<br> particles Ca?

valentina_108 [34]

Answer:

$\boxed {\boxed {\sf 592,826,303.6 \ moles \ of \ Ca }}$

Explanation:

To convert from moles to particles, we must Avogadro's Number.

$6.022*10^{23}$

This number tells us the number of particles (atoms, ions, molecules, etc.) in 1 mole of a substance. In this case, it is the particles of calcium in 1 mole of calcium.

$6.022*10^{23} \ particles \ Ca / mole \ Ca$

We can use Avogadro's Number as a ratio or fraction.

$\frac{6.022 *10^{23} \ particles \ Ca}{1 \ mol \ Ca}$

Multiply this by the given number of particles (3.57*10³²).

$3.57*10^{32} \ particles \ Ca*\frac{6.022 *10^{23} \ particles \ Ca}{1 \ mol \ Ca}$

Flip the fraction so the particles of calcium will cancel out.

$3.57*10^{32} \ particles \ Ca*\frac{1 \ mol \ Ca}{6.022 *10^{23} \ particles \ Ca}$

$3.57*10^{32} *\frac{1 \ mol \ Ca}{6.022 *10^{23} }$

$\frac{3.57*10^{32} \ mol \ Ca}{6.022 *10^{23} }$

$592826303.6 \ mol \ Ca$

There are <u>592,826,303.6 moles</u> of calcium in 3.57*10³² particles of calcium.

8 0

2 years ago

The ksp of manganese(ii) carbonate, mnco3, is 2.42 × 10-11. calculate the solubility of this compound in g/l.

Vikki [24]

Answer : The solubility of this compound in g/L is $565.414\times 10^{-6}g/L$ .

Solution : Given,

$K_{sp}=2.42\times 10^{-11}$

Molar mass of $MnCO_3$ = 114.945g/mole

The balanced equilibrium reaction is,

$MnCO_3\rightleftharpoons Mn^{2+}+CO^{2-}_3$

At equilibrium s s

The expression for solubility constant is,

$K_{sp}=[Mn^{2+}][CO^{2-}_3]$

Now put the given values in this expression, we get

$2.42\times 10^{-11}=(s)(s)\\2.42\times 10^{-11}=s^2\\s=0.4919\times 10^{-5}=4.919\times 10^{-6}moles/L$

The value of 's' is the molar concentration of manganese ion and carbonate ion.

Now we have to calculate the solubility in terms of g/L multiplying by the Molar mass of the given compound.

$s=4.919\times 10^{-6}moles/L\times 114.945g/mole=565.414\times 10^{-6}g/L$

Therefore, the solubility of this compound in g/L is $565.414\times 10^{-6}g/L$ .

8 0

3 years ago

Does carbon ever leave the EARTH? Explain.

GrogVix [38]

Answer:

Carbon is also found in the atmosphere where it's a part of carbon dioxide gas emitted when fossil fuels are burned and when living organisms breathe. It's in organic matter in the soil, and it's in rocks. But far and away the most carbon on Earth is stored in a surprising place: the ocean. Carbon is also found in the atmosphere where it's a part of carbon dioxide gas emitted when fossil fuels are burned and when living organisms breathe. It's in organic matter in the soil, and it's in rocks. But far and away the most carbon on Earth is stored in a surprising place: the ocean.

Hope this helps!

8 0

3 years ago

Think about how particles are arranged inside atoms. Please name and describe those three particles, and describe how the partic

vekshin1

Protons : positive charge , about same mass as neutrons , in the nucleus

neutrons : no charge , about the same mass as a proton , in the nucleus

electrons : negative charge , less mass than protons and neutrons , in orbitals outside of the nucleus

8 0

3 years ago

a child runs 60m race with an average speed of 4 m/s.how long did the child take to complete the race? give the correct unit for

Elis [28]

Answer:

option c. i took the quiz

Explanation:

8 0

3 years ago