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soldier1979 [14.2K]
2 years ago
15

A baseball player throws a baseball at a speed of 40 meters per second at an angle of 30 degrees. What is the velocity of projec

tile at 2 second?​
Physics
2 answers:
jeka57 [31]2 years ago
8 0

Answer:35m/s

Explanation:The horizontal component of the velocity is the cosine of 30 degrees multiplied by 40m/s. The cosine of 30 degrees is the 0.8660 (check this on your Regents Reference Tables or on your calculator). To get the speed, multiply by 40m/s. This equals 34.64, which is approximately 35m/s.

Vesna [10]2 years ago
3 0

Answer:

The horizontal component of the velocity is the cosine of 30 degrees multiplied by 40m/s. The cosine of 30 degrees is the 0.8660 . To get the speed, multiply by 40m/s. This equals 34.64, which is approximately 35m/s.

Hope it helpss :)

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Earth's gravity acts upon objects with a steady force of __________. A. 8. 9 meters per second B. 9. 8 meters per minute C. 8. 9
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9.8 meters per second squared

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8 0
2 years ago
Two particles with masses m and 3m are moving toward each other along the x axis with the same initial speeds Vi. Particle m is
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Answer:

v1 = \sqrt{(2)}Vi

v2 = \sqrt{(2/3)}Vi

ANGLE is 35.3 degree celcius

Explanation:

Given data:

mass m and 3m

initial speed Vi

particle with mass m is moving toward left while particle with mass 3m is moving toward right

By using conservation of momentum :

mVi + 3m(-Vi) = mv1 +3mv2

-2mVi = m(v1 + 3v2)

-2Vi = v1 + 3v2

conservation of energy :

m(Vi^2) + 3m(-Vi^2) = mv1^2 + 3mv2^2

4mVi^2 = m(v1^2+3v2^2)

4Vi^2 = v1^2+3v2^2

After collision, particle with mass m moves at right angles, thus by considering conservation of momentum in x & y direction,

x direction : -2mVi = 3m.v2i

-2Vi = 3v2i

y direction : 0 = m(v1)j+3m(v2)j

-v1j = 3v2j

subsitute these value in energy conservation

v1 = \sqrt{(2)}Vi

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8 0
3 years ago
Suppose 2.10 C of positive charge is distributed evenly throughout a sphere of 1.30-cm radius. 1) What is the charge per unit vo
Anuta_ua [19.1K]

Answer:

\rho=2.28\times 10^5\ C/m^3

Explanation:

Given that,

Charge, Q = 2.1 C

The radius of sphere, r = 1.3 cm = 0.013 m

We need to find the charge per unit volume for this situation. It can be calculated a follows:

\rho=\dfrac{Q}{\dfrac{4}{3}\pi r^3}\\\\\rho=\dfrac{2.1}{\dfrac{4}{3}\pi \times (0.013)^3}\\\\\rho=2.28\times 10^5\ C/m^3

So, the charge per unit volume is 2.28\times 10^5\ C/m^3.

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2 years ago
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