Answer: There are 0.00269 moles of acetic acid in buffer.
Explanation:
To calculate the number of moles for given molarity, we use the equation:
.....(1)
Molarity of acetic acid solution = 0.0880 M
Volume of solution = 30.6 mL
Putting values in equation 1, we get:

Thus there are 0.00269 moles of acetic acid in buffer.
Producer, Primary consumers, Secondary consumers and Tertiary consumers.
Answer:
See explanation
Explanation:
When water reacts with formic acid, The following equilibrium is set up;
HCOOH(aq) + H20(l) ⇄ HCOO-(aq) + H30+(aq)
This is because, the water abstracts a proton from formic acid to form its conjugate base, formate ion.
At equilibrium, the forward is favored.
The answer is 80 atomic mass
I think 14 are produced because if you go up by that you get it