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3 years ago

15

A ball is dropped and bounces off the floor. Its speed is the same immediately before and immediately after the collision. Which

of the following is true about the collision between the ball and the floor?
a) The ball's momentum is conserved.
b) The ball's momentum changes direction but not magnitude.
c) The ball's momentum changes magnitude but not direction.
d) The impulse delivered to the ball by the floor is zero.
e) The impulse delivered to the floor by the ball is zero.

1 answer:

Korolek [52]3 years ago

7 0

Answer:

option B.

Explanation:

The correct answer is option B.

when the ball drops, the velocity of the ball before the collision is v

After the collision, the velocity of the ball is the same but in the opposite direction.

Impulse delivered to the ball and the floor, in this case, is not zero.

The magnitude of the momentum remains the same but the direction of the ball changes.

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Brayden and Riku now use their skills to work a problem. Find the equivalent resistance, the current supplied by the battery and

Liono4ka [1.6K]

a) $5 \Omega$ , 1.6 A

b) $6 \Omega$ , 1.33 A

Explanation:

a)

In this situation, we have two resistors connected in series.

The equivalent resistance of resistors in series is equal to the sum of the individual resistances, so in this circuit:

$R=R_1+R_2$

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$R_2=1 \Omega$

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Now we can use Ohm's Law to find the current flowing through the circuit:

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b)

In this part, a third resistor is added in series to the circuit; so the new equivalent resistance of the circuit is

$R=R_1+R_2+R_3$

where:

$R_1=4\Omega\\R_2=1\Omega\\R_3=1\Omega$

Substituting, we find the equivalent resistance:

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Now we can find the current through the circuit by using again Ohm's Law:

$I=\frac{V}{R}$

where

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bekas [8.4K]

Answer:

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Explanation:

To find the distance between the first order bright fringe and the central peak, can be calculated by using the following formula:

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D: distance from the screen = 5.50 m

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ym: height of the m-th fringe

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For λ = 470 nm = 470*10^-9 m

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