I think its C building a barrier wall
Answer:
0.306mm
Explanation:
The radius of the conductor is 3mm, or 0.003m
The area of the conductor is:
A = π*r^2 = π*(.003)^2 = 2.8*10^-5 m^2
The current density is:
J = 130/2.8*10^-5 = 4.64*10^6 A/m
According to the listed reference:
Vd = J/(n*e) = 4.64*10^6 / ( 8.46*10^28 * 1.6*10^-19 ) = 0.34*10^-6 m/s = 0.34mm/s
The distance traveled is:
x = v*t = 0.34 * .90 = 0.306 mm
Mass = force/acceleration
M=24/ 6
m=4 N
Complete Question
A parallel plate capacitor contains a positively charged plate on the left, and a negatively charged plate on the right. An electron in between the plates is moving to the right. Which statement is true?
Group of answer choices
a The potential energy of the electron is decreasing and it is moving to a region having a higher potential
b The potential energy of the electron is decreasing and it is moving to a region having a lower potential.
c The potential energy of the electron is increasing and it is moving to a region having a lower potential
d The potential energy of the electron is increasing and it is moving to a region having a higher potential.
Answer:
The correct option is C
Explanation:
From the question we are told that
An electron in between the plates is moving to the right
Generally the potential energy of the electron is mathematically represented as
Here e is the charge on the electron and V is the electric potential of the electron
Generally the left side with the positive charge has a higher potential than the right side with the negative charge
Now when the potential energy of the electron increases it will move toward the plate with the lower potential which is the left plate
To solve this problem we will start by differentiating the values in each of the states of matter. Subsequently through the thermodynamic tables we will look for the values related to the entropy, enthalpy and respective specific volumes. Through the relationship of Power defined as the product between mass and enthalpy and mass, specific volume and pressure, we will find the energetic values in the two states investigated. We will start defining the states
State 1
From steam table
Now
<em>As 1-2 is isentropic</em>
State 2
From steam table
PART A) The power produced by turbine is the product between the mass and the enthalpy difference, then
b) Pump Work
State 3
The Work done by the pump is