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olya-2409 [2.1K]
3 years ago
12

Why can't sodium bond with potassium?

Chemistry
1 answer:
const2013 [10]3 years ago
8 0
Since both elements have a +1 charge, they cannot lose or gain electrons to form a bond. Plus they are both metals, so it wouldn't form a natural bond
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Which of the following statements about Ideal Gas Law is supported by Charles's Law?
grin007 [14]

Answer:

B

Explanation:

volume occupied by fixed amount of gas is directly proportional to its absolute temperature.

5 0
3 years ago
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Compound A has molecular formula C5H11Br. When compound A is treated with bromine in the presence of UV light, the major product
damaskus [11]

The compound (A) is 2-bromo-pentane. See attached picture for the chemical diagram.

Explanation:

2-bromo-pentane (A) reacts with bromine (Br₂) under UV light to form 2,2-dibromopentane and HBr. Also 2-bromo-pentane (A) reacts with NaSH to from pentane-2-thiol, which have an asimetric carbon, and NaBr.

You may find the chemical reactions and diagrams of the compounds in the attached picture.

Learn more about:

structure of organic compounds

brainly.com/question/9315917

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6 0
3 years ago
1) Which of the following is the smallest unit of a chemio<br> Tallest unit of a chemical element?
solong [7]

Answer:

Nanomachines will work with atoms, not nuclei. The smallest unit of a chemical element, about a third of a nanometer in diameter. Atoms make up molecules and solid objects.

Explanation:

6 0
3 years ago
Name the reactants and products of Na3PO4 + 3KOHàNaOH + K3PO4 <br> (Question 2 and 3)
Leona [35]

Answer:

Question 2: Na3PO4, KOH; Question 3: Na3PO4, KOH

Explanation:

Question 2

The reactants in a chemical equation are the species on the left side of the reaction arrow.

Thus the reactants are Na3PO4, KOH (sodium phosphate and potassium hydroxide).

Question 3.

The products in a chemical equation are the species on the right side of the reaction arrow.

Thus the products are NaOH, K3PO4 (sodium hydroxide and potassium phosphate).

6 0
4 years ago
. An inflated balloon has a volume of 6.0 L at sea level (1.0 atm) and is allowed to ascend in altitude until the pressure is 0.
Tju [1.3M]

Answer:

The answer to your question is Volume = 11.4 L

Explanation:

Data

Volume 1 = V1 = 6 L

Pressure 1 = P1 = 1 atm

Temperature 1 = T1 = 22°C

Volume 2 = V2 = ?

Pressure 2 = 0.45 atm

Temperature 2 = -21°C

Process

1.- Convert temperature (°C) to °K

T1 = 273 + 22 = 295°K

T2 = 273 + (-21) = 252°K

2.- Use the combined gas law to solve this problem

                   P1V1 / T1 = P2V2 / T2

-Solve for V2

                   V2 = P1V1T2 / T1P2

-Substitution

                   V2 = (6)(1)(252) / (295)(0.45)

- Simplification

                   V2 = 1512 / 132.75

- Result

                   V2 = 11.38 L

3 0
3 years ago
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