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4 years ago

Which is the intersection of the sets R={0, 1, 2, 4}, S={4, 9, 12, 13}, T={13, 15, 19, 20}?

Mathematics

2 answers:

Zepler [3.9K]4 years ago

8 0

Answer:

Null set

Step-by-step explanation:

4 intersects sets R and S but not T

13 intersects sets S and T but not R

So this would result as a null set.

Sonbull [250]4 years ago

8 0

Answer:

$R\cap S\cap T= \{ \} \text{ or } \phi \text{ aka null/empty/void set}$

since there is no common element in all the three sets.

since intersection is associative,

you can do it in simpler ways as:

$L \cap (R \cap T) = \{0,1,2,3,4\}\cap\left(\{4,9,12,13\}\cap\{13,15,19,20\}\right) \\ =\{0,1,2,3,4\}\cap(\{13\} = \phi$

$(L \cap R) \cap T = \left(\{0,1,2,3,4\}\cap\{4,9,12,13\}\right)\cap\{13,15,19,20\} \\ =\{4\}\cap(\{13,15,19,20\} = \phi$

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Dennis_Churaev [7]

ANSWER TO QUESTION 1

$f(x)=(x-2)(x+3)(x-1)^2$ .

EXPLANATION

The function given to us is,

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This implies that

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$f(1.5)=-0.56\:$

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3 years ago

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gtnhenbr [62]

Answer:

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This is a simultaneous equation.

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4 years ago

Read 2 more answers