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Bingel [31]
4 years ago
8

A student uses a spring loaded launcher to launch a marble vertically in the air. The mass of the marble is

Physics
1 answer:
GarryVolchara [31]4 years ago
8 0

Answer:

Part a)

When spring compressed by 2 cm

H = 1.47 m

Part b)

When spring is compressed by 4 cm

H = 5.94 m

Explanation:

Part a)

As we know that the spring is compressed and released

so here spring potential energy is converted into gravitational potential energy at its maximum height

So we will have

\frac{1}{2}kx^2 = mg(H + x)

0.5(220)(0.02)^2 = 0.003(9.81)(H + 0.02)

so we have

H = 1.47 m

Part b)

Similarly when spring is compressed by 4 cm

then we have

\frac{1}{2}kx^2 = mg(H + x)

0.5(220)(0.04)^2 = 0.003(9.81)(H + 0.04)

so we have

H = 5.94 m

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A is at absolute zero, which is pretty much impossible, and definitely does not describe a gas. We rule this out immediately.

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PLZ MARK ME AS BRAINLEIST ;)

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Answer:

\theta=5.71^{o}

Explanation:

In order to solve this problem, we mus start by drawing a free body diagram of the given situation (See attached picture).

From the free body diagram we can now do a sum of forces in the x and y direction. Let's start with the y-direction:

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so now we can find our angle:

\theta=tan^{-1}(0.10)

so

\theta=5.71^{o}

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