Answer:
<h2>1139.5 J</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
work done = 265 × 4.3 = 1139.5
We have the final answer as
<h3>1139.5 J</h3>
Hope this helps you
The particle has constant acceleration according to

Its velocity at time
is



Then the particle has position at time
according to


At at the point (3, 6, 9), i.e. when
, it has speed 8, so that

We know that at some time
, the particle is at the point (5, 2, 7), which tells us

and in particular we see that

and

Then



That is, there are two possible initial velocities for which the particle can travel between (3, 6, 9) and (5, 2, 7) with the given acceleration vector and given that it starts with a speed of 8. Then there are two possible solutions for its position vector; one of them is

The person's horizontal position is given by

and the time it takes for him to travel 56.6 m is

so your first computed time is the correct one.
The question requires a bit of careful reading, and I think there may be a mistake in the problem. The person's vertical velocity
at time
is

which tells us that he would reach the ground at about
. In this time, he would have traveled

But we're told that he is caught by a net at 56.6 m, which would mean that the net cannot have been placed at the same height from which he was launched. However, it's possible that the moment at which he was launched doesn't refer to the moment the cannon went off, but rather the moment at which the person left the muzzle of the cannon a fraction of a second after the cannon was set off. After this time, the person's initial vertical velocity
would have been a bit smaller than
.
Hello there, Goodmorning and God Bless...Here is your answer to your following question:
yessss i do!!!
Answer:
Total time taken=110 seconds
Total distance traveled=480m
Explanation:
First of all, we find the total time taken:
For that, we use the formula : Distance/Speed= Time
Time for part 1 : 200/5=40 seconds
Time for part 2 : 280/4=70seconds
Total time taken=110 seconds
Total distance traveled=480m
Average Speed= 480/110=4.36 m/s
Total displacement=200-280=-80m (Since this is displacement, we need to find the distance between the initial and final point. Also, I've taken east direction as positive and west as negative)
Average Velocity=-80/110=-0.72 m/s
OR 0.72m/s towards west.