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oksian1 [2.3K]
2 years ago
8

Two cars collide at an intersection. One car has a mass of 1300 kg and is

Physics
2 answers:
Nata [24]2 years ago
8 0

Answer:B

Explanation:sorry they removed my answer for some reason.

kotegsom [21]2 years ago
6 0

Answer: B

Explanation: Sorry these brainly trolls deleted my first one

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3. Applying Concepts Explain why a canoe that has hollow, water-
Alekssandra [29.7K]

Answer:

I may be wrong

Explanation:

it it won't collapse because it is like a log logs don't sink when they are in water

5 0
3 years ago
Scientist have changed the model of the atom.what experimental evidence led them to change from the previous model .
Thepotemich [5.8K]

Rutherford's model of the atom (ESAAQ) Rutherford carried out some experiments which led to a change in ideas around the atom. His new model described the atom as a tiny, dense, positively charged core called a nucleus surrounded by lighter, negatively charged electrons.

7 0
3 years ago
An ideal spring with spring constant k is hung from the ceiling. The initial length of the spring, with nothing attached to the
hram777 [196]

The mass m of the object = 5.25 kg

<h3>Further explanation</h3>

Given

k = spring constant = 3.5 N/cm

Δx= 30 cm - 15 cm = 15 cm

Required

the mass m

Solution

F=m.g

Hooke's Law

F = k.Δx

\tt m.g=k.\Delta x\\\\m.10=3.5\times 15\\\\m=5.25~kg

7 0
3 years ago
The parachute on a drag racing car deploys at the end of a run. If the car has a mass of 820 kg and the car is moving 36 m/s, wh
Lelechka [254]

In order to determine the required force to stop the car, proceed as follow:

Calculate the deceleration of the car, by using the following formula:

v^2=v^2_o-2ax

where,

v: final speed = 0m/s (the car stops)

vo: initial speed = 36m/s

x: distance traveled = 980m

a: deceleration of the car= ?

Solve the equation above for a, replace the values of the other parameters and simplify:

\begin{gathered} a=\frac{v^2_o-v^2}{2x} \\ a=\frac{(36\frac{m}{s})^2-(0\frac{m}{s})^2}{2(980m)}=0.66\frac{m}{s^2} \end{gathered}

Next, consider that the formula for the force is:

F=ma

where,

m: mass of the car = 820 kg

a: deceleration of the car = 0.66m/s^2

Replace the previous values and simplify:

F=(820kg)(0.66\frac{m}{s^2})=542.20N

Hence, the required force to stop the car is 542.20N

4 0
1 year ago
What is 6.9 × 107 written in standard form?
n200080 [17]
Answer: 6.9x 107 in standard form is 69,000,000

7 0
3 years ago
Read 2 more answers
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