Answer:
4 Joules (if you mean 2000 grams)
4000 Joules (if you mean 2000 kilograms)
Explanation:
<h2><u><em>
PLEASE MARK AS BRAINLIEST!!!!!</em></u></h2>
B) I just took the test and put D but it gave me the wrong answer. It told me it was B.
Answer: Improvement Invention means any CCIA Invention and CCIA's rights as a joint owner in a Joint Invention that is sufficiently different from the scope of a Licensed Patent to be separately patentable, and covered by the claims of Licensed Patents.
The component of the force in negative z-direction is -0.144 N.
The given parameters;
- <em>current in the wire, I = 2.7 A</em>
- <em>length of the wire, L = (3.2 i + 4.3j) cm</em>
- <em>magnetic filed, B = 1.24 i</em>
The force on the segment of the wire is calculated as follows;
![F = ILBsin(\theta)](https://tex.z-dn.net/?f=F%20%3D%20ILBsin%28%5Ctheta%29)
where;
- <em>θ is the angle wire and magnetic field</em>
<em />
The force on the wire segment will be perpendicular in negative z-direction (applying right hand rule), so there won't be any x and y component of the force.
The angle between the wire and the magnetic field is calculated as follows;
![\theta = tan^{-1} (\frac{y}{x} )\\\\\theta = tan^{-1} (\frac{4.3}{3.2} )\\\\\theta = 53.3 \ ^0](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20tan%5E%7B-1%7D%20%28%5Cfrac%7By%7D%7Bx%7D%20%29%5C%5C%5C%5C%5Ctheta%20%3D%20tan%5E%7B-1%7D%20%28%5Cfrac%7B4.3%7D%7B3.2%7D%20%29%5C%5C%5C%5C%5Ctheta%20%3D%2053.3%20%5C%20%5E0)
The magnitude of the wire length is calculated as follows;
![|l | = \sqrt{3.2^2 + 4.3^2} = 5.36 \ cm = 0.0536 \ m](https://tex.z-dn.net/?f=%7Cl%20%7C%20%3D%20%5Csqrt%7B3.2%5E2%20%2B%204.3%5E2%7D%20%3D%205.36%20%5C%20cm%20%3D%200.0536%20%5C%20m)
The component of the force in negative z-direction is calculated as;
![F_z = -ILB sin(\theta)\\\\F_z = -2.7 \times 0.0536 \times 1.24 \times sin(53.3)\\\\F_z = -0.144 \ N](https://tex.z-dn.net/?f=F_z%20%3D%20-ILB%20sin%28%5Ctheta%29%5C%5C%5C%5CF_z%20%3D%20-2.7%20%5Ctimes%200.0536%20%5Ctimes%201.24%20%5Ctimes%20%20sin%2853.3%29%5C%5C%5C%5CF_z%20%3D%20-0.144%20%5C%20N)
Thus, the component of the force in negative z-direction is -0.144 N.
Learn more here:brainly.com/question/22719779