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kati45 [8]
3 years ago
13

mini stereo speaker cables are made of copper wire surrounded by robert electricity travel down the copper portion of the cable

while the rubber protects you from being zapped by the electricity which physical property explains the difference in ability of copper and rubber to transmit electricity
Physics
1 answer:
Tom [10]3 years ago
7 0

Here current is flowing through the copper wire so this shows that copper is good conductor of electricity.

It is having less resistance as it conducts the current easily

Now a rubber coating on it will protect us from electric shock

So this property shows that rubber is a bad conductor of electricity

It is having large electrical resistance due to which it will conduct no current

Rubber : - No transmittance of electricity

copper :- good transmittance of electricity

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José and Laurel measured the length of a stick's shadow during the day. Without knowing the length of the stick, which of their
skelet666 [1.2K]

Answer:

Option B.

Explanation:

Assuming the stick is in vertical position, its shadow depends on two factors: its length and the angle between the sun rays and the stick. When the angle is bigger, the lenght of the shadow increases, and vice versa. So, when the sun rays are parallel to the stick, the shadow may be small. Since they are nearly perpendicular to the Earth's surface at 12 o'clock, the shadow of the stick at that time should be minimal. It means that the measured shadow of 75 cm at 12:30 p.m. is almost impossible (Option B).

5 0
3 years ago
A bimetallic strip (brass/steel), which is straight at room temperature, will be immersed in boiling water and allowed to equili
lakkis [162]

The thermal expansion of the materials allows to find the deflection of the bimetallist strip is Δy = 3.48 cm

given paramers

    * Bimetallic brass / steel tape

    * Initial temperature, room temperature T = 20ºC

    * Final temperature, boiling water  = 100ºC

    * initial length L₀ = 222mm (1cm / 10mm) = 22.2cm

    * thickness of bimetallic tape e = 0.036 inch (2.54 cm/1 inch) = 0.0914 cm

to find

    * perpendicular deviation or deflection (Δy)

Thermal expansion is the phenomenon of change in the length of a body due to the change in temperature, due to the increase in the length of the atomic and molecular bonds, macroscopically it is described by

        ΔL = α L₀ ΔT

ΔL and ΔT are the variation of the length and temperature respectively, L₀ is the initial length and α the coefficient of expansion ends.

In this case we have a strip formed by two materials with different coefficient of thermal expansion,

Brass       α_{brass}   = 19 10⁻⁶ ºC⁻¹

Steel       α_{steel}    = 11 10⁻⁶ ºC⁻¹

In the attached we can see a diagram of the process, as the temperature increases, the material with greater thermal expansion lengthens more, so the system must curve towards the center of the material with less

thermal expansion. Let's find the length of the strip for each material

brass          L_{f brass} - L₀ = α_{brass} L₀ ΔT

Steel           L_{f steel} - L₀ = \alpha_{steel} L₀ ΔT

Note that the initial length is the same for the two materials and that the strip is in thermal equilibrium at room temperature.

If we assume that we have an arc of circumference, we can write the length of the arc

        θ = L / r

where θ is the angle in radines, L the length of the arc and r the radius of curvature, let's write this equation for each material

brass     L_{f \ brass} =θ r₁

steel      L_{f \ steel} = θ r₂

we substitute in our equations

           θ r₁ - L₀ = α_{brass} L₀ ΔT

           θ r₂ - L₀ = α_{steel} L₀ ΔT

let's subtract the two equations

           θ (r₁- r₂) = L₀ ΔT (α_{brass} - α_{steel})

the thickness of the strip is

           e = r₁ -r₂

           θ = Lo \ \Delta T \ \frac{\alpha_{brass} - \alpha_{steel}}{e}

we calculate

           θ = 22.2 \ (100-20) \ \frac{(19-11) \ 10^{-6}}{0.0914}

           θ = 0.155 rad

Let's use trigonometry to find the perpendicular deflection

          tan θ = Δy / L₀

          Δy = L₀ tan θ

          Δy = 22.2 tan 0.155

          Δy = 3.48 cm

Using the thematic expansion of the two materials we find the deflection of the bimetallist strip is 3.38 cm

Learn more about thermal expansion here: brainly.com/question/18717902

7 0
3 years ago
What is the approximate uncertainty in the area of a circle of radius 4.5×10^4 cm? Express your answer using one significant fig
Igoryamba

Answer:

A=6.36\times 10^5\ m^2

Explanation:

It is given that,

Radius of the circle, r=4.5\times 10^4\ cm=4.5\times 10^2\ m

The area of the circle is given by :

A=\pi r^2

A=\pi (4.5\times 10^2\ m)^2

A=636172.51\ m^2

or

A=6.36\times 10^5\ m^2

As there is no uncertainty given in the radius of the circle. So, the area of the circle is 6.36\times 10^5\ m^2. Hence, this is the required solution.

5 0
3 years ago
A force of 100 N acts upward. Resolve this force into 2 components; one that acts 30º north of west and one that acts 60º north
GrogVix [38]

To resolve these forces we have to make use of the sines and cosines.

To resolve this force in 30 degree north of west, the answer will be

100*sin(30)

The answer will be 50N

Now to resolve the force acting 60 degree north of east

100* cos(60)

The answer will be 50N.

This also adds to the total force acting that is 50+50=100N. This is the way forces are resolved according to their specified angles.

5 0
3 years ago
In a photoelectric effect experiment, electrons emerge from a copper surface with a maximum kinetic energy of 1.10 eV when light
Sladkaya [172]

Answer:A) 220 nm

Explanation:

Given

Maximum Kinetic Energy K.E.=1.10 eV

Work Function W=4.65 eV

from Einstein Equation

h\mu =W+K.E.

h\cdot \frac{c}{\lambda }=W+K.E.

h\cdot \frac{c}{\lambda }=4.65+1.10

6.626\times 10^{-34}\cdot \frac{3\times 10^8}{\lambda }=5.75

1 eV=1.6\times 10^{-19} J

thus 5.75 eV=9.2\times 10^{-19} J

\lambda =\frac{6.626\times 10^{-34}\time 3\times 10^8}{9.2\times 10^{-19}}

\lambda =216.06 nm\approx 220 nm

6 0
3 years ago
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