HI is strong acid, so:
[H+] = [HI]
[H+] = 6 × 10^-3 M
pH = -log[H+]
pH = -log(6 × 10^-3) = 2,22
:-) ;-)
Answer: is neither an acid nor a base
Explanation: Water is a universal solvent which means it can dissolve most of the substances in it.
Water has high thermal heat capacity , which means large heat is required to heat the water.
Water is not always pure as it gets contaminated by various pollutants present in the atmosphere such as gases, bacteria and suspended matter.
Water is an amphoteric substance which can act as both acid and base, thus can donate and acept [texH^+[/tex] ions.Thus it is neither an acid nor a base.

Here water is accepting a proton, thus it acts as base.

Here water is donating a proton, thus it acts as acid.
Answer:
0.1593 L.
Explanation:
- We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and P are constant, and have two different values of V and T:
<em>P₁V₁T₂ = P₂V₂T₁</em>
<em></em>
P₁ = 600 torr/760 = 0.789 atm, V₁ = 185.0 mL = 0.185 L, T₁ = 25.0°C + 273 = 298.0 K.
P₂ (at STP) = 1.0 atm, V₂ = ??? L, T₂ (at STP = 0.0°C) = 0.0°C + 273 = 273.0 K.
<em>∴ V₂ = P₁V₁T₂/P₂T₁</em> = (0.789 atm)(0.185 mL)(298.0 K)/(1.0 atm)(273.0 K) = <em>0.1593 L.</em>
Hydrochloric acid and sodium hydroxide
HCl + NaOh ----> NaCl + H2O