Hey, lovely! It's a pretty lengthy process but here is a pretty clear video on how to do it. Hope this helps ya!
https://www.khanacademy.org/science/chemistry/chemical-reactions-stoichiome/balancing-chemical-equat...
Answer:
i) 0,7 molH20/s
ii)11,2 g O/s
iii)1,4 g H/s
Explanation:
i) To find the molar flow rate of water, we just convert the mass of water to moles of water using its molecular weight(g/mol) and changing to the proper units (lb to grames and hours to seconds):

ii) Now we just consider the oxygen in the water stream (for 1 mole of water there is 1 mole of oxygen):

iii)Just considering the hydrogen in the stream (for 1 mole of water there is 2 moles of hydrogen):

Explanation:
It is known that for high concentration of
, reduction will take place. As, cathode has a positive charge and it will be placed on left hand side.
Now,
= 0 and the general reaction equation is as follows.

3.00 M n = 2 30 mM
E = 
= 
= 0.038 V
Therefore, we can conclude that voltage shown by the voltmeter is 0.038 V.
Your answer is correct.
MgO(s) + H2O(l) ----> Mg(OH)2(aq)
:-) ;-)
Answer:
Explanation:
0
All the charges of the protons are cancelled out by all the charges on the electrons.