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nata0808 [166]
3 years ago
11

Rb2co3(aq)+fec2h302(aq)-->

Chemistry
1 answer:
nata0808 [166]3 years ago
4 0

Answer:

Rb2CO3(aq)+Fe(C2H3O2)2(aq)--> 2Rb(C2H3O2)(aq) + FeCO3(s)

Explanation:

The reaction shown in the answer is the reaction of rubidium carbonate and iron II acetate. Rubidium is far more reducing than Fe II hence it can displace Fe II from its salt as shown.

The reducing property of metals depends on the value of their individual electrode potential values. For rubidium, its standard reduction potential is -2.98 V while that of Fe II is -0.44V. Hence rubidium can displace Fe II from its salt as shown above.

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It is being added! <3

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Which of the following has a central atom that exceeds the octet rule? PCl5 BeF2 H2S CO2
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Schwarzschild Radius here.

So,

The octet rule really only holds up for the second period elements, and only certain elements in that period, for that matter.  Elements in the third periods and beyond can have expanded octets.

Draw Lewis dot diagrams for each molecule.

PCl_5 :

P is the central atom bonded individually to each Cl.  The only logical diagram is that with three lone pairs surrounding each Cl and the P single-bonded to each Cl atom.  If you count the bonds, you will find that P has five pairs, or 10 electrons.  This exceeds the octet rule.

BeF_2 :

The Lewis dot diagram for this molecule is a linear molecule with the Be in the center, singly bonded to both F's, each of which have three lone pairs.  This means Be has only two pairs, or four electrons.  While not an example of a central atom that exceeds the octet rule, Be is one of the special elements that can stably have an incomplete octet.

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Hope this helps!
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If the pattern shown continued, the next low tide occurred on Day 3 at approximately
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9A. A sample of hydrogen at 1.56 atm had it's pressure decreased to 0.73
densk [106]

Answer:

351.43mL

Explanation:

To calculate the original volume of hydrogen gas in this question, the Boyle's law equation will be used. Boyle's law equation is:

P1V1 = P2V2

Where; P1 = initial pressure

V1 = initial volume

P2 = final pressure

V2 = final volume

According to this question, the P1= 1.56atm, V1 = ?, P2 = 0.73atm, V2 = 751mL

Hence;

P1V1 = P2V2

1.56 × V1 = 0.73 × 751

1.56 V1 = 548.23

V1 = 548.23/1.56

V1 = 351.43mL

Therefore, the original volume of hydrogen gas is 351.43 mL.

4 0
3 years ago
List four observations that suggest chemical change is occurring
allsm [11]

Answer:

Examples of Chemical Changes

Burning wood.

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Digesting food.

Cooking an egg.

Heating sugar to form caramel.

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