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nata0808 [166]
3 years ago
11

Rb2co3(aq)+fec2h302(aq)-->

Chemistry
1 answer:
nata0808 [166]3 years ago
4 0

Answer:

Rb2CO3(aq)+Fe(C2H3O2)2(aq)--> 2Rb(C2H3O2)(aq) + FeCO3(s)

Explanation:

The reaction shown in the answer is the reaction of rubidium carbonate and iron II acetate. Rubidium is far more reducing than Fe II hence it can displace Fe II from its salt as shown.

The reducing property of metals depends on the value of their individual electrode potential values. For rubidium, its standard reduction potential is -2.98 V while that of Fe II is -0.44V. Hence rubidium can displace Fe II from its salt as shown above.

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Magnesium reacts steadily with hydrochloric acid
balu736 [363]

Magnesium + Hydrocloric acid -> Magnesium chloride + hydrogen

You can observe a single displacement reaction

"Describe to show that the has formed is hydrogen"

I don't know what you mean. I can show the chemical equation though.

Mg(s) + 2 HCl(aq) --> MgCl 2(aq) + H 2(g)

3 0
3 years ago
How many moles of copper are present in a sample that contains 4.55 x 10^24 atoms of copper
FinnZ [79.3K]

Hope you could understand.

If you have any query, feel free to ask.

3 0
2 years ago
7. In a remote area of Columbia, kids have to travel to school on a zip-line!
andriy [413]

Answer:

yes

Explanation:

Kids like fun things, and school is not fun , so if kids got to go to school on a zipline, attendance would be through the roof!

6 0
3 years ago
What pressure is required to achieve a co2 concentration of 7.90×10−2 m at 20∘c?
Savatey [412]

Answer:-  1.90 atm

Solution:- It is based on combined gas law equation, PV = nRT

In this equation, P is pressure, V is volume, n is moles of gas, R is universal gas constant and T is kelvin temperature.

If we divide both sides by V then:

P=\frac{nRT}{V}

We know that, molarity is moles per liter. So, in the above equation we could replace \frac{n}{V} by molarity, M of the gas. The equation becomes:

P = MRT

T = 20 + 273 = 293 K

M = 7.9*10^-^2

Let's plug in the values in the equation:

P = (7.9*10^-^2)(0.0821)(293)

P = 1.90 atm

So, the pressure of the gas is 1.90 atm.

7 0
3 years ago
A compound is found to contain 73.23% xenon name 26.77% oxygen by mass. What is the empirical formula for this compound ?
Luba_88 [7]

The empirical formula is XeO₃.

<u>Explanation:</u>

Assume 100 g of the compound is present. This changes the percents to grams:

Given mass in g:

Xenon = 73.23 g

Oxygen = 26.77 g

We have to convert it to moles.

Xe = 73.23/   131.293 = 0.56 moles

O = 26.77/ 16 = 1.67 moles

Divide by the lowest value, seeking the smallest whole-number ratio:

Xe = 0.56/ 0.56 = 1

O = 1.67/ 0.56 = 2.9 ≈3

So the empirical formula is XeO₃.

6 0
3 years ago
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