Answer:
2Li + F₂ → 2LiF
Explanation:
The reaction expression is given as:
Li + F₂ → LiF
We are to balance the expression. In that case, the number of atoms on both sides of the expression must be the same.
Let use a mathematical approach to solve this problem;
Assign variables a,b and c as the coefficients that will balance the expression:
aLi + bF₂ → cLiF
Conserving Li: a = c
F: 2b = c
let a = 1, c = 1 and b =
Multiply through by 2;
a = 2, b = 1 and c = 2
2Li + F₂ → 2LiF
Explanation:
For the given reaction, the temperature of liquid will rise from 298 K to 339 K. Hence, heat energy required will be calculated as follows.
Putting the given values into the above equation as follows.
=
= 1902.81 J
Now, conversion of liquid to vapor at the boiling point (339 K) is calculated as follows.
= energy required =
= latent heat of vaporization
Therefor, calculate the value of energy required as follows.
=
=
= 12121.2 J
Therefore, rise in temperature of vapor from 339 K to 373 K is calculated as follows.
Value of = 1.06 J/g,
= (373 -339) K = 34 K
Hence, putting the given values into the above formula as follows.
=
= 983.892 J
Therefore, net heat required will be calculated as follows.
Q =
= 1902.81 J + 12121.2 J + 983.892 J
= 15007.902 J
Thus, we can conclude that total energy (q) required to convert 27.3 g of THF at 298 K to a vapor at 373 K is 15007.902 J.