Answer:
the final mole of the flexible container = 12.92 moles
Explanation:
Given that :
initial volume of a flexible container = 6.13 L
initial mole of a flexible container = 6.51 mol
final volume of a flexible container = 18.3 L
final mole of a flexible container = ???
Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.
Therefore,
n = 19.43
19.43 = 6.51 + n₂
n₂ = 19.43 - 6.51
n₂ = 12.92 moles
Thus; the final mole of the flexible container = 12.92 moles
Make a fizzing volcano with facts and pictures of a volcano
Answer:
Mass = 15.1 g
Explanation:
Given data:
Number of moles of NaBH₄ = 0.40 mol
Mass in gram = ?
Solution:
Formula:
Mass = number of moles × molar mass
Molar mass of NaBH₄ = 37.83 g/mol
By putting values,
Mass = 0.40 mol × 37.83 g/mol
Mass = 15.1 g
The answer is going to be 476.06.
Answer: After 4710 seconds, 1/8 of the compound will be left
Explanation:
Using the formulae
Nt/No = (1/2)^t/t1/2
Where
N= amount of the compound present at time t
No= amount of compound present at time t=0
t= time taken for N molecules of the compound to remain = 4710 seconds
t1/2 = half-life of compound = 1570 seconds
Plugging in the values, we have
Nt/No = (1/2)^(4710s/1570s)
Nt/No = (1/2)^3
Nt/No= 1/8
Therefore after 4710 seconds, 1/8 molecules of the compound will be left
