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Irina-Kira [14]
4 years ago
15

The atoms of which elements are least likely to form chemical bonds? Check all that apply.

Chemistry
2 answers:
svetoff [14.1K]4 years ago
4 0
The elements that apply are argon, neon and helium. These elements are called inert gasses and have unique properties that make them unreactive. These elements are so unreactive that they are classified as chemically inert.
The elements belong to a group in the periodic table known as the Noble Gases. They belong to family 18 of the periodic table and have atoms with 8 valence electrons. This configuration causes the gases to be unreactive.
pogonyaev4 years ago
3 0

Answer:

A

Explanation:

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What is the change in gravitational potential energy of an apple with a mass of 0.25 kg if it falls 0.7 m from a table. Estimate
Drupady [299]

Answer:

1.71675 J

Explanation:

Please mark Brainliest?

Hope this helps!

8 0
3 years ago
Choose a likely identity for X, Y, and Z in these structures. A central X atom is bonded to two chlorine atoms through single bo
11111nata11111 [884]

Answer:

X= Be

Y= B

Z=O

Explanation:

From the description of the compound XCl2, among the options listed only beryllium can form such compound with three lone pairs in the two chlorine atoms and no lone pair on the central atom X.

From the description of YCl3, only Boron among the options listed can form such a compound with no lone pair on the central atom and three lone pairs on each of the chlorine atoms.

From the description of ZCl2, only oxygen forms the compound OCl2 among the elements listed where oxygen possesses two lone pairs and each chlorine atom possesses three lone pairs each.

8 0
3 years ago
Adi loves the smell of lavender, so she decides to press a few petals of the flower until they release a few drops of oil. She w
soldier1979 [14.2K]

Answer:

See Explanation

Explanation:

What Adi failed to realize is that the oily substance that was obtained from lavender consists of a mixture of substances. It is not only the required  fragrance that is present in the extract.

This experiment will not work because those other components in the mixture may be erroneously identified when they show up in the mass spectrum of the extract and may be mistaken for the fragrance in question.

Hence the experiment will not work because; if some kind of separation method is not used to identify other impurities in the oil, many other substances may be mistaken for the actual fragrance.

4 0
3 years ago
Consider the addition of an electron to the following atoms from the fourth period. Rank the atoms in order from the most negati
lesya [120]

Answer:

Ge: [Ar] 3d10 4s2 4p2 => 6 electrons in the outer shell

Br: [Ar] 3d10 4s2 4p5 => 7 electrons in the outer shell

Kr: [Ar] 3d10 4s2 4p6 => 8 electrons in the outer shell

Explanation:

The electron affinity or propension to attract electrons is given by the electronic configuration. Remember that the most stable configuration is that were the last shell is full, i.e. it has 8 electrons.

The closer an atom is to reach the 8 electrons in the outer shell the bigger the electron affinity.

Of the three elements, Br needs only 1 electron to have 8 electrons in the outer shell, so it has the biggest electron affinity (the least negative).

Ge: needs 2 electrons to have 8 electrons in the outer shell, so it has a smaller (more negative) electron affinity than Br.

Kr, which is a noble gas, has 8 electrons and is not willing to attract more electrons at all, the it has the lowest (more negative) electron affinity of all three to the extension that really the ion is so unstable that it does not make sense to talk about a number for the electron affinity of this atom.

Read more on Brainly.com - brainly.com/question/1832586#readmore

6 0
3 years ago
A 7.12 L cylinder contains 1.21 mol of gas A and 4.94 mol of gas B, at a temperature of 28.1 °C. Calculate the partial pressure
GenaCL600 [577]

Answer:

P_A=4.20atm\\\\P_B=17.1atm

Explanation:

Hello!

In this case, since the equation for the ideal gas is:

PV=nRT

For each gas, given the total volume, temperature (28.1+273.15=301.25K) and moles, we can easily compute the partial pressure as shown below:

P_A=\frac{n_ART}{V} =\frac{1.21mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_A=4.20atm\\\\P_B=\frac{n_BRT}{V} =\frac{4.94mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_B=17.1atm

Best regards!

8 0
3 years ago
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