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3 years ago

^^^^^^^^^^^^^^^^^^^^

Mathematics

2 answers:

zheka24 [161]3 years ago

8 0

Answer:

The correct answer is option B

Step-by-step explanation:

From the figure we can see a number of line segments

To find the value of x

Let the point of intersection of line segments be 'o'

From the figure we get, <KON and <MOL are vertically opposite angles

m<KON = m<MOL

90 + 15 = 5x

5x = 105

x = 105/5 = 21

Therefore the value of x = 21

tangare [24]3 years ago

3 0

Answer:

The correct answer option is B. 21.

Step-by-step explanation:

We are given a figure where the line KL is intersecting another line MN such that angle from K to N is equal to the angle opposing it which is the angle measuring $(5x)$ .

Measure of angle K - N = 90° + 15° = 105°

Since angle K - N = angle M - L, we can write it as:

105° = 5x

x = 105/5

x = 21

Therefore, the correct answer option is B. 21.

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The box plots show the weights, in pounds, of the dogs in two different animal shelters. Weights of Dogs in Shelter A 2 box plot

Romashka [77]

Answer:

Shelter A

Step-by-step explanation:

For Shelter A: the whiskers range from 8 to 30

so, the minimum weight of Shelter A is 8 pounds.

For For Shelter B: the whiskers range from 10 to 28

so, the minimum weight of Shelter B is 10 pounds.

Which animal shelter has the dog that weighs the least?

The answer is: Shelter A

Note: whiskers are plotted are from the minimum to Q1 and from Q2 to the max.

See the attached figure.

4 0

3 years ago

Read 2 more answers

WILL GIVE BRAINLIEST

shutvik [7]

Answer:

s=12569 may be

but I am not sure

7 0

2 years ago

I need a few answers 1. P+15=-2 p=? 2. 8y=-64 y=? 3. -2 x 6 =? 4. H-(-4) for H=8

Nikitich [7]

1: -17 + 15 = -2 P = -17
2: 8 x -8 = -64 y = -8
3: -2 x 6 = -12
4: 8 - (-4) = 12
Hope I Helped

5 0

3 years ago

Use the substitution of x=e^{t} to transform the given Cauchy-Euler differential equation to a differential equation with consta

kherson [118]

By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dt}=x\dfrac{\mathrm dy}{\mathrm dx}$

which follows from $x=e^t\implies t=\ln x\implies\dfrac{\mathrm dt}{\mathrm dx}=\dfrac1x$ .

$\dfrac{\mathrm dy}{\mathrm dt}$ is then a function of $x$ ; denote this function by $f(x)$ . Then by the product rule,

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1x\dfrac{\mathrm dy}{\mathrm dt}\right]=-\dfrac1{x^2}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac1x\dfrac{\mathrm df}{\mathrm dx}$