All categories

3 years ago

^^^^^^^^^^^^^^^^^^^^

Mathematics

2 answers:

zheka24 [161]3 years ago

8 0

Answer:

The correct answer is option B

Step-by-step explanation:

From the figure we can see a number of line segments

To find the value of x

Let the point of intersection of line segments be 'o'

From the figure we get, <KON and <MOL are vertically opposite angles

m<KON = m<MOL

90 + 15 = 5x

5x = 105

x = 105/5 = 21

Therefore the value of x = 21

tangare [24]3 years ago

3 0

Answer:

The correct answer option is B. 21.

Step-by-step explanation:

We are given a figure where the line KL is intersecting another line MN such that angle from K to N is equal to the angle opposing it which is the angle measuring $(5x)$ .

Measure of angle K - N = 90° + 15° = 105°

Since angle K - N = angle M - L, we can write it as:

105° = 5x

x = 105/5

x = 21

Therefore, the correct answer option is B. 21.

You might be interested in

The box plots show the weights, in pounds, of the dogs in two different animal shelters. Weights of Dogs in Shelter A 2 box plot

Romashka [77]

Answer:

Shelter A

Step-by-step explanation:

For Shelter A: the whiskers range from 8 to 30

so, the minimum weight of Shelter A is 8 pounds.

For For Shelter B: the whiskers range from 10 to 28

so, the minimum weight of Shelter B is 10 pounds.

Which animal shelter has the dog that weighs the least?

The answer is: Shelter A

Note: whiskers are plotted are from the minimum to Q1 and from Q2 to the max.

See the attached figure.

4 0

3 years ago

Read 2 more answers

WILL GIVE BRAINLIEST

shutvik [7]

Answer:

s=12569 may be

but I am not sure

7 0

2 years ago

I need a few answers 1. P+15=-2 p=? 2. 8y=-64 y=? 3. -2 x 6 =? 4. H-(-4) for H=8

Nikitich [7]

1: -17 + 15 = -2 P = -17
2: 8 x -8 = -64 y = -8
3: -2 x 6 = -12
4: 8 - (-4) = 12
Hope I Helped

5 0

2 years ago

Use the substitution of x=e^{t} to transform the given Cauchy-Euler differential equation to a differential equation with consta

kherson [118]

By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dt}=x\dfrac{\mathrm dy}{\mathrm dx}$

which follows from $x=e^t\implies t=\ln x\implies\dfrac{\mathrm dt}{\mathrm dx}=\dfrac1x$ .

$\dfrac{\mathrm dy}{\mathrm dt}$ is then a function of $x$ ; denote this function by $f(x)$ . Then by the product rule,

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1x\dfrac{\mathrm dy}{\mathrm dt}\right]=-\dfrac1{x^2}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac1x\dfrac{\mathrm df}{\mathrm dx}$