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3 years ago

Three metal spoons are on a table. They are each at room temperature. If the three spoons touch.

Physics

2 answers:

hoa [83]3 years ago

3 0

If the three spoon touch nothing happens because they are all at room Temperature

liubo4ka [24]3 years ago

3 0

Same temp= no reaction

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Identify the physical property of a material that plays an important role in determining if the collision is elastic or not base

Nutka1998 [239]

Answer:

They are spherical and hollow (not compact or dense)

Explanation:

An elastic collision is a form of a collision where kinetic energy and momentum are conserved in the process. When there is zero loss of kinetic energy and momentum, it is called a perfectly elastic collision.

This form of collision is observed in atmospheric gases and colliding balls which happens to be spherical and hollow.

7 0

3 years ago

A charge of 0.20uC is 30cm from a point charge of 3.0uC in vacuum. what work is required to bring the 0.2uC charge 18cm closer t

vlada-n [284]

Answer:

The correct answer is " $4.49\times 10^{10} \ joules$ ".

Explanation:

According to the question,

The work will be:

⇒ $Work=-\frac{kQq}{R}$

$=-\frac{1}{4 \pi \varepsilon \times (18-30)\times 3\times 0.2}$

$=-\frac{1}{4 \pi \varepsilon \times (-12)\times 3\times 0.2}$

$=\frac{0.3978}{\varepsilon }$

$=4.49\times 10^{10} \ joules$

Thus the above is the correct answer.

3 0

3 years ago

You are traveling in a convertible with the top down. The car is moving at a constant velocity 22.5 m/s, due east along flat gro

Ray Of Light [21]

Answer:

The car moved a distance $x=48.6m$ .

Explanation:

First we need to know: <em>How much time will the tomato spend in the air?</em>

From Kinematics: $v_y(t)=v_0_y+at$

where $v_0_y=10.6\frac{m}{s}$ and $a=-g=-9.8\frac{m}{s^2}$ is gravity's acceleration.

$v_y(t)=v_0_y-gt$

When the tomato touches the car again, $v_y=-v_0_y=-10.6\frac{m}{s}$

Then, we have:

$t=\frac{v_y-v_o_y}{-g}$ ⇒ $t=\frac{v_y-v_o_y}{-g}=2.16s$

Also from Kinematics we have: $x(t)=v_xt$

Which is very simple because we can take initial position 0 and there's no acceleration in the x direction. And $v_x=22.5\frac{m}{s}$

So, taking $t=2.16s$

$x=48.6m$

3 0

3 years ago

Imagine that treble sounds could travel at 400 m/s, but bass sounds traveled at only 300 m/s. If sound actually behaved that way

kirza4 [7]

Answer:

$\Delta t = 0.1s$

Explanation:

We need to calculate the difference between the times the waves from the bass sounds ( $t_b$ ) and treble sounds ( $t_t$ ) take to reach us, that is, $\Delta t = t_b-t_t$ .