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Grace [21]
3 years ago
5

List each FITT principle and describe what they represent. will mark brainliest!!!

Physics
2 answers:
elena-s [515]3 years ago
8 0

Answer: FITT↓

<em>Frequency</em>: refers to the frequency of exercise undertaken or how often you exercise.

<em>Intensity</em>: refers to the intensity of exercise undertaken or how hard you exercise.

<em>Time</em>: refers to the time you spend exercising or how long you exercise for.

<em>Type</em>: refers to the type of exercise undertaken or what kind of exercise you do.

Explanation:

Hope this helps

VLD [36.1K]3 years ago
3 0

Answer:Frequency: How often is the exercise completed? Intensity: How difficult is the exercise? Time: What is the duration of the exercise? Type: What kind of exercise is being completed, and how is it beneficial?

please give branliest. this is the only way i can help

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A small block with mass 0.0400 kg slides in a vertical circle of radius 0.600 m on the inside of a circular track. During one of
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Explanation:

Given that

The mass of the body is 0.04kg

M=0.04kg

The radius of the paths is 0.6m

r=0.6m

The normal force exerted at A is 3.9N

Fa=3.9N

The normal force exerted at B is 0.69N

Fb=0.69N

Then work done by friction from point A to B will be the change in K.E

W=∆K.E+P.E

So we need to know the velocity at both point A and B

Then since the centripetal force is given as

Ft=mv²/r

Then,

For point A

Fa=mv²/r

3.9=0.04v²/0.6

3.9=0.0667v²

v²=3.9/0.0667

v²=58.5

v=√58.5

v=7.65m/s

Va=7.65m/s

Now at point B

Fb=mv²/r

0.69=0.04v²/0.6

0.69=0.0667v²

v²=0.69/0.0667

v²=10.35

v=√10.35

v=3.22m/s

Vb=3.22m/s

Then, the work done is

W=∆K.E+P.E

P.E is given as mgh

The height will be 2R =1.2m

P.E=mgh

P.E=0.04×9.81×1.2

P.E=0.471J

Final kinetic energy at B minus initial kinetic energy at A

W=K.Eb-K.Ea

K.E is given as 1/2mv²

W=1/2m(Vb²-Va²) +P.E

W=0.5×0.04(3.22²-7.65²) +0.471

W=0.5×0.04×(-48.1541) +0.471

W=-0.96+0.471

W=-0.49J

work was done on the block by friction during the motion of the block from point A to point B is 0.49J.

Friction opposes motions and that is why the work done is negative

3 0
3 years ago
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