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Grace [21]
4 years ago
5

List each FITT principle and describe what they represent. will mark brainliest!!!

Physics
2 answers:
elena-s [515]4 years ago
8 0

Answer: FITT↓

<em>Frequency</em>: refers to the frequency of exercise undertaken or how often you exercise.

<em>Intensity</em>: refers to the intensity of exercise undertaken or how hard you exercise.

<em>Time</em>: refers to the time you spend exercising or how long you exercise for.

<em>Type</em>: refers to the type of exercise undertaken or what kind of exercise you do.

Explanation:

Hope this helps

VLD [36.1K]4 years ago
3 0

Answer:Frequency: How often is the exercise completed? Intensity: How difficult is the exercise? Time: What is the duration of the exercise? Type: What kind of exercise is being completed, and how is it beneficial?

please give branliest. this is the only way i can help

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Express the length of a marathon run of<br> 26 mi 385 yd in meters.<br> Answer in units of m.
hjlf

Answer:

1 mi = 5280 ft  * 12 in/ft = 63360 in

A convenient conversion factor (to remember) is 1 m = 39.37 in

63360 in / (39.37 in / m) = 1609.3 m

26 mi + 285 m = 26 * 1609.3 + 385 = 42,228 m

6 0
3 years ago
A box of weight w=2.0N accelerates down a rough plane that is inclined at an angle ϕ=30∘ above the horizontal, as shown (Figure
Nesterboy [21]

Answer:

<h2>The work done is 0.882 Joules.</h2>

Explanation:

To calculate the work, we need to find all forces that are involved in the movement.

As you can analyse, the body is the force that make the box to move, and the friction force is opposite to it, we cannot forget about the friction. So, we have to calculate the resultant force to this context.

F_{R}=W_{x}-F_{k}

So, to find W_{x} we use: W_{x}=W.sen\phi; where W=2N;\phi = 30\°

W_{x}=2N.sin30\°=1\frac{1}{2}N=1N

The friction force would be:

F_{k}=\mu_{k}N=(0.30)(1.7N)=0.51

Then, the resultant force is:

F_{R}=W_{x}-F_{k}

F_{R}=1N-0.51N=0.49N

Now, we calculate the work: W=F_{R} d

W=(0.49N)(1.8m)=0.882J

Therefore, the work done is 0.882 Joules.

7 0
4 years ago
Read 2 more answers
Problem 3: A basketball player is running at 4.75 m/s toward the basket when he jumps into the air to dunk the ball. He maintain
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Answer

given,

speed of the basketball player, v_x = 4.75 m/s

height of the jump = ?

a) initial vertical velocity = 0 m/s

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   v² = 14.7

   v = 3.83 m/s

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    t = \dfrac{3.83}{9.8}

         t = 0.39 s

    horizontal distance

             = v_x  × t

             = 4.75 × 0.39

             = 1.85 m

horizontal distance is equal to 1.85 m

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