Answer:
<em>262.4 m/s</em>
<em></em>
Explanation:
The complete question is
If we ignore air resistance, a falling body will fall 16t^2 feet in t seconds. What is the average velocity between t=8 and t=8.4? Round your answer to two decimal places if necessary.
The distance fallen s = 16t^2
The velocity v = 
= 32t
If we substitute the values of t into the velocity v, we'll have
at t = 8 s, V1 = 32 x 8 = 256 m/s
at t = 8.4 s, V2 = 32 x 8.4 = 268.8 m/s
Average velocity = (V2 - V1)/2 = (268.8 + 256)/2 = <em>262.4 m/s</em>
The easiest, non-technical way to think about it is like this:
-- A scalar is a quantity that has a size but no direction.
Those include temperature, speed, cost, volume, distance, etc.
One number is all there is to know about it, and there's no way you can
add more of the same stuff to it that would cancel both of them out.
-- A vector is a quantity that has a size and also has a direction.
Those include force, displacement, velocity, acceleration, etc.
It takes more than one number to completely describe one of these.
Also, if you combine two of the same vector quantity in different ways,
you can get different results, and they can even cancel each other out.
Here are some examples. Notice that in each of these examples,
every speed has a direction that goes along with it. This turns the
scalar speed into a vector velocity.
If you're walking inside a bus, and the bus is driving along the road,
then your velocity along the road is the sum of your walking velocity
inside the bus plus the velocity of the bus along the road.
-- If you're walking north up the middle of the bus at 2 miles per hour
and the bus is driving north along the road at 20 miles per hour, then
your velocity along the road is 22 miles per hour north.
-- If you're walking south towards the back of the bus at 2 miles per hour
and the bus is driving north along the road at 5 miles per hour, then your
velocity along the road is 3 miles per hour north.
-- If you're walking south towards the back of the bus at 2 miles per hour
and the bus is just barely rolling north along the road at 2 miles per hour,
then your velocity along the road is zero.
-- If you're in a big railroad flat-car that's rolling north along the track
at 2 miles per hour, and you walk across the flat-car towards the east
at 2 miles per hour, then your velocity along the ground is 2.818 miles
per hour toward the northeast.
Answer:
Explanation:
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Answer:
a) 1.6 mN b) -1.6 mN c) -1.6 mN d) 1.6 mN
Explanation:
The electrostatic force between 2 point charges, obeys the Coulomb's Law, that can be expressed as follows:
F₁₂ = k*q₁*q₂/(r₁₂)² (in magnitude)
The direction of the force, is along the line that joins the charges (along the x axis) and as q₁ and q₂ are of the same sign, aims away from both charges.
a) So, for the force on q₂, we have:
F₁₂ = 9*18*10⁻⁵ N = 1.6 mN (positive as it is aiming in the positive x direction)
b) The force on q1, according to Newton's 3rd Law, is just equal and opposite to the one on q2:
F₂₁ = (-9*18*10⁻⁵) N = -1.6 mN (towards the negative x direction, away from q1)
c) If q₂ were -6.0 μC, the force will be the same in magnitude, but as now both charges have different signs, they wil attract each other, so the direction of the forces will be exactly the opposite to the first case:
F₁₂ = -1.6 mN (going towards the origin, where q₁ is located)
F₂₁ = 1.6 mN (going in the positive x direction, towards q₂)
