Answer:
C) formaldehyde, H2C=O.
Explanation:
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In this case, given that the hydrogen bondings are known as partial intermolecular interactions between a lone pair on an electron rich donor atom, particularly oxygen, and the antibonding molecular orbital of a bond between hydrogen and a more electronegative atom or group. Thus, among the options, C) formaldehyde, H2C=O, will exhibit hydrogen bonding since the lone pair of electrons of the oxygen at the carbonyl group, are able to interact with hydrogen (in the form of water).
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For example:
5Cl₂ + I₂ + 12NaOH = 10NaCl + 2NaIO₃ + 6H₂O
Na₂S₂O₃ + 4I₂ + 10NaOH = 8NaI + 2Na₂SO₄ + 5H₂O
Answer:
As metals are giant lattice structures, the number of electrostatic forces to be broken is extremely large
Explanation:
This means that the melting point and boiling point of metals are more similar to those for ionic compounds than for covalent substances.
There is a specific formula to use for these type of problems.
ln (P2/ P1)= Δvap/ R x (1/T1 - 1/T2)
R= 8.314
P1= 92.0 torr
T1= 23 C + 273= 296 K
P2= 351.0 torr
T2= 45.0 C + 273= 318 K
plug the values and solve for the unknown
ln( 351.0/ 92.0)= Δvap/ 8.314 x (1/296 - 1/318)
Δvap= 47630.6 joules