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lora16 [44]
3 years ago
13

Momentum is usually not exactly conserved in a real world demonstration of momentum conservation. What is a possible reason for

this fact?
Physics
1 answer:
Maksim231197 [3]3 years ago
5 0

Answer:

For any collision occurring in an isolated system, momentum is conserved. The total amount of momentum of the collection of objects in the system is the same before the collision as after the collision.

Explanation:

Hope this helps

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Weight on planet Mars ​
Sunny_sXe [5.5K]

Mars: 0.38

weight = mass x surface gravity

multiplying your weight on Earth by the number above will give you your weight on the surface of Mars

If you weigh 150 pounds (68 kg.) on Earth, you would weigh 57 lbs. (26 kg.) on Mars

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3 years ago
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You exert a force of 25 newtons while you move a rock 15 meters. How much work did you perform?
leonid [27]
Work Done = Force x Distance Moved
Work Done = 25 x 15 = 375 Joules
4 0
3 years ago
you are sitting at the center of a large turntable at an amusement park as it is set spinning freely. you decide to crawl toward
larisa [96]

You are sitting at the center of a large turntable at an amusement park as it is set spinning freely. You decide to crawl towards the edge of the turntable. Rotational speed will decrease

There is no external torque

hence , the angular momentum of the table is conserved

L (initial) = L ( final)

since , L = m*v*r

where

m = mass

v = velocity

r = radius

If  the person is crawled towards the outer rim, then the rotational inertia of the turntable will increase. In order to conserve the angular momentum , its rotational speed will decrease as mass and radius cannot be altered .

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7 0
1 year ago
A potentialiterence of 12 volts is induced across a straight wire 0.20 meters long as it is moved at a constant speed of 3.0 met
shtirl [24]

Strength of the magnetic field: 20 T

Explanation:

For a conductive wire moving perpendicular to a magnetic field, the electromotive force (voltage) induced in the wire due to electromagnetic induction is given by

\epsilon=BvL

where

B is the strength of the magnetic field

v is the speed of the wire

L is the length of the wire

For the wire in this problem, we have:

\epsilon=12 V (induced emf)

L = 0.20 m (length of the wire)

v = 3.0 m/s (speed)

Solving  for B, we find the strength of the magnetic field:

B=\frac{\epsilon}{vL}=\frac{12}{(0.20)(3.0)}=20 T

Learn more about magnetic fields:

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6 0
3 years ago
URGENT PLEASE HELP!!!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (29pt
Furkat [3]

Chemical=B

Mechanical=C

Nuclear=A

Electromagnetic=D

Thermal=E

I think these are right but if not I’m sorry

Hope I helped :]

5 0
2 years ago
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