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Montano1993 [528]
3 years ago
9

If I have 6 moles of a gas at a pressure of 5.8 atm and a volume of 12 liters, what

Chemistry
1 answer:
poizon [28]3 years ago
7 0

The temperature of the system is 141.36K.

<h3><u>Explanation</u>:</h3>

According to the universal gas law, the pressure of a gas is directly proportional to the absolute temperature and number of moles of the gas and inversely proportional to the volume of the gas.

So in equation format,

\frac{P\times V}{n\times T} =constant.

Or\frac{P\times V}{n\times T}= R.

Here R is called the universal gas constant which has different values in different units.

Here the unit of volume is in litres and unit of pressure is in atmosphere.

So. Value of R comes as =0.082057\frac{L\times atm} {K\times mole}.

So, according to the question,

P is 5.8atm, V is 12 litres and n is 6 moles.

So, 5.8\times12 = 6\times0.082057\times T.

Or, T = \frac{5.8\times12} {6\times0.082057}.

Or, T = 141.36.

So,the temperature of the system is 141.36K

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So A

Explanation:

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3 years ago
2A(g) + B(l) ⇌ 3C(aq) + D(s)
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8 0
3 years ago
If 42.8 mL of 0.204 M HCl solution is needed to neutralize a solution of Ca(OH)2, how many grams of Ca(OH)2 must be in the solut
Aneli [31]

Hey There!

At neutralisation moles of H⁺ from HCl  = moles of OH⁻ from Ca(OH)2  so :

0.204 * 42.8 / 1000  => 0.0087312 moles

Moles of Ca(OH)2 :

2 HCl + Ca(OH)2 = CaCl2 + 2 H2O

0.0087312 / 2 => 0.0043656 moles (  since each Ca(OH)2 ives 2 OH⁻ ions )

Therefore:

Molar mass Ca(OH)2 = 74.1 g/mol

mass = moles of Ca(OH)2 * molar mass

mass =  0.0043656 * 74.1

mass = 0.32 g of Ca(OH)2


Hope that helps!

6 0
3 years ago
Match the chemical with the statement that best describes the observed change in the rate of the reaction when the concentration
maria [59]

Answer:

Explanation:

When the amount of H2O2 is doubled while KI is kept constant, the rate of reaction doubles.

When the amount of KI is doubled and the amount of H2O2 is halved, the rate stays nearly constant.

2H2O2 (aq) → O2(g) + 2H2O (l) ------------- first order kinetics reaction.

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H2O2 + I– -> IO– + H2O (Step 1)

H2O2 + IO– -> I– + H2O + O2 (Step 2)

It can be seen that the iodine ion (provided by the KI solution) is a product as well as a reactant.

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8 0
2 years ago
calculate pressure exerted by 1.255 mol of CI2 in a volume of 5.005 L at a temperature 273.5 k using ideal gas equation
balu736 [363]

Answer:

The pressure is 5.62 atm.

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

In this case:

  • P= ?
  • V= 5.005 L
  • n= 1.255 mol
  • R= 0.082 \frac{atm*L}{mol*K}
  • T= 273.5 K

Replacing:

P* 5.005 L= 1.255 mol* 0.082 \frac{atm*L}{mol*K} *273.5 K

Solving:

P=\frac{1.255 mol* 0.082 \frac{atm*L}{mol*K} *273.5 K}{5.005 L}

P= 5.62 atm

<u><em>The pressure is 5.62 atm.</em></u>

8 0
2 years ago
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