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torisob [31]
2 years ago
12

I NEED HELP PLEASE! :) Describe a limiting reactant in your own words.

Chemistry
2 answers:
snow_tiger [21]2 years ago
4 0
The reactant in a chemical reaction that limits the amount of product that can be formed.
koban [17]2 years ago
3 0

Answer:

See explanation

Explanation:

A limiting reactant is the reactant in a reaction that is done reacting first, because there are less moles of it than are needed for a full reaction with the other compound or compounds.

Hope this helps!

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Which type of fuel can only be used in certain geographic area? A. natural gas B. nuclear C. solar D. Biomass
poizon [28]

Answer:

A

Explanation:

6 0
3 years ago
How many moles of silicon are in 5.9 X 10 to the 24 power atoms of silicon​
Dimas [21]

Answer:

9.79740949850 moles

Explanation:

  • 1 mole = Avogardo's Number <<6.022 E 23 <<particles, atoms, etc.>>
  • This problem can be solved using dimensional analysis by multiplying atoms (5.9E24 atoms) by (1) mole and then dividing the number by Avogardo's number (6.022 E 23 atoms).
  • Note: E = * 10

Side Note: Please let me know if you need any clarifications about this!

8 0
2 years ago
Read 2 more answers
An analytical chemist is titrating of a solution of nitrous acid with a solution of . The of nitrous acid is . Calculate the pH
Burka [1]

Answer:

pH = 2.69

Explanation:

The complete question is:<em> An analytical chemist is titrating 182.2 mL of a 1.200 M solution of nitrous acid (HNO2) with a solution of 0.8400 M KOH. The pKa of nitrous acid is 3.35. Calculate the pH of the acid solution after the chemist has added 46.44 mL of the KOH solution to it.</em>

<em />

The reaction of HNO₂ with KOH is:

HNO₂ + KOH → NO₂⁻ + H₂O + K⁺

Moles of HNO₂ and KOH that react are:

HNO₂ = 0.1822L × (1.200mol / L) = <em>0.21864 moles HNO₂</em>

KOH = 0.04644L × (0.8400mol / L) = <em>0.0390 moles KOH</em>

That means after the reaction, moles of HNO₂ and NO₂⁻ after the reaction are:

NO₂⁻ = 0.03900 moles KOH = moles NO₂⁻

HNO₂ = 0.21864 moles HNO₂ - 0.03900 moles = 0.17964 moles HNO₂

It is possible to find the pH of this buffer (<em>Mixture of a weak acid, HNO₂ with the conjugate base, NO₂⁻), </em>using H-H equation for this system:

pH = pKa + log₁₀ [NO₂⁻] / [HNO₂]

pH = 3.35 + log₁₀ [0.03900mol] / [0.17964mol]

<h3>pH = 2.69</h3>
8 0
3 years ago
What does this picture represent?​
Shtirlitz [24]

Answer:

idk buddy

don't know

Explanation:

I don't know

7 0
3 years ago
URGENT!!! What is the balanced form of this equation?
Ostrovityanka [42]

Explanation: This is a reaction of oxidation of H_2O_2 in the presence of acidified KMnO_4. Acidified KMnO_4 is a strong oxidizing agent.

To balance out the H^+ on the reactant side, we write H_2O on the product side.

Balancing out the following reaction gives us:

2MnO_4^-+6H^++5H_2O_2\rightarrow 2Mn^{2+}+8H_2O+5O_2

5 0
3 years ago
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