Ask question

Ask question

All categories

Makovka662 [10]

2 years ago

7

a burning candle wax reacts with oxygen. after a glass jar is placed over it, the candle goes out. what is the limiting reactant

?

2 answers:

trapecia [35]2 years ago

5 0

Answer:

The Oxygen

Explanation:

When fire is covered, it goes out due to the lack of oxygen to maintain itself.

USPshnik [31]2 years ago

4 0

The limiting reactant in the experiment of the burning candle is oxygen.

<h3>What is a limiting reactant?</h3>

A limiting reactant is a reactant which determines the amount of product that ca be formed in a given reaction.

The limiting reactant is always used up in a reaction, after which the reaction stops.

In the experiment of the burning candle, covering the candle with the glass prevents more oxygen from taking part in the reaction.

Therefore, the limiting reactant is oxygen.

Learn more about limiting reactant at: brainly.com/question/14225536

#SPJ11

You might be interested in

Is this right:) please tell me

viva [34]

Answer:

I think that:

The tendency of an object to resist changes in motion: inertia

Attractive force:gravity

And everything else is right

Explanation:

I am not a physicist

But I passed physics with an A

4 0

3 years ago

What is the iupac nomenclature of diethyl methane

grin007 [14]

Answer:

In chemical nomenclature, the IUPAC nomenclature of organic chemistry is a systematic method of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC). ... IUPAC names can sometimes be simpler than older names, as with ethanol, instead of ethyl alcohol.

Explanation:

In chemical nomenclature, the IUPAC nomenclature of organic chemistry is a systematic method of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC). ... IUPAC names can sometimes be simpler than older names, as with ethanol, instead of ethyl alcohol.

7 0

3 years ago

The energy of a photon needed to cause ejection of an electron from a photoemissive metal is expressed as the sum of the binding

slega [8]

Answer:

$Binding\ energy=43.43\times 10^{-20}\ J$

Explanation:

Using the expression for the photoelectric effect as:

$E=h\nu_0+\frac {1}{2}\times m\times v^2$

Also, $E=\frac {h\times c}{\lambda}$

$\nu_0=\frac {c}{\lambda_0}$

Applying the equation as:

$\frac {h\times c}{\lambda}=\frac {hc}{\lambda_0}+\frac {1}{2}\times m\times v^2$

Where,

h is Plank's constant having value $6.626\times 10^{-34}\ Js$

c is the speed of light having value $3\times 10^8\ m/s$

$\lambda$ is the wavelength of the light being bombarded

Given, $\lambda=4.00\times 10^{-7}\ m$

$\frac {hc}{\lambda_0}$ is the binding energy or threshold energy

$\frac {1}{2}\times m\times v^2$ is the kinetic energy of the electron emitted. = $6.26\times 10^{-20}\ J$

Thus, applying values as:

$\frac{h\times c}{\lambda}=Binding\ Energy+Kinetic\ Energy$

$\frac{6.626\times 10^{-34}\times 3\times 10^8}{4.00\times 10^{-7}}\ J=Binding\ Energy+6.26\times 10^{-20}\ J$

$\frac{19.878}{10^{19}\times \:4}\ J=Binding\ Energy+6.26\times 10^{-20}\ J$

$49.69\times 10^{-20}\ J=Binding\ Energy+6.26\times 10^{-20}\ J$

$Binding\ energy=43.43\times 10^{-20}\ J$

5 0

3 years ago

A solid powder is composed of molecules containing silver (Ag), nitrogen (N), and oxygen (O) atoms. All of the molecules are ide

Nat2105 [25]

Answer is in the file below

tinyurl.com/wpazsebu

6 0

3 years ago

Read 2 more answers

Which conversion factor do you use first to calculate the number of grams of CO 2 produced by the reaction of 50.6 g of CH 4 wit

Brilliant_brown [7]

Answer:

Thus, first conversion of mass of methane into moles by dividing it with 16.04 g/mol

Mass = 138.63 g

Explanation:

The balanced chemical reaction is shown below:-

$CH_4+2O_2\rightarrow CO_2+2H_2O$

Firstly the moles of methane gas reacted must be calculate as:-

Given, mass of methane = 50.6 g

Molar mass of methane gas = 16.04 g/mol

The formula for the calculation of moles is:-

$Moles=\frac{Mass\ taken}{Molar\ mass}=\frac{50.6}{16.04}\ mol=3.15\ mol$

Thus, from the reaction stoichiometry,

1 mole of methane produces 1 mole of carbon dioxide

Also,

3.15 mole of methane produces 3.15 mole of carbon dioxide

Moles of $CO_2$ = 3.15 mole

Molar mass of $CO_2$ = 44.01 g/mol

Mass = Moles*Molar mass = $3.15\times 44.01$ g = 138.63 g

3 0

3 years ago