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2 years ago

Charles' Law

Physics

1 answer:

SpyIntel [72]2 years ago

8 0

Therefore, the volume of the gas at temperature 100°C is 4.62L

Explanation:

Given-

Volume, V1 = 4L

Temperature, T1 = 50°C = 50 + 273K = 323K

Temperature, T2 = 100°C = 100 + 273K = 373K

Volume, V2 = ?

Using Charles law:

V1/T1 = V2/T2

4/323 = V2/373

V2 = 4.62L

Therefore, the volume of the gas at temperature 100°C is 4.62L

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An isolated conducting sphere has a 10 cm radius. One wire carries a current of 1.000 002 0 A into it. Another wire carries a cu

romanna [79]

Answer:

t = 5.56 ms

Explanation:

Given:-

- The current carried in, Iin = 1.000002 C

- The current carried out, Iout = 1.00000 C

- The radius of sphere, r = 10 cm

Find:-

How long would it take for the sphere to increase in potential by 1000 V?

Solution:-

- The net charge held by the isolated conducting sphere after (t) seconds would be:

qnet = (Iin - Iout)*t

qnet = t*(1.000002 - 1.00000) = 0.000002*t

- The Volt potential on the surface of the conducting sphere according to Coulomb's Law derived result is given by:

V = k*qnet / r

Where, k = 8.99*10^9 ..... Coulomb's constant

qnet = V*r / k

t = 1000*0.1 / (8.99*10^9 * 0.000002)

t = 5.56 ms

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2 years ago

In a hydroelectric power plant, water flows from an elevation of 400 ft to a turbine, where electric power is generated. For an

VashaNatasha [74]

Answer:

$V=3.475ft^3/s=3.48ft^3/s$

Explanation:

We have here values from SI and English Units. I will convert the units to English Units.

We hace for the power P,

$P= 100kW \rightarrow 100kW*(\frac{737.56ft.lbf/s}{1kW})$

$P= 73.7*10^{3}ft.lbf/s$

we have other values such $h=400ft$ and $\gamma= 62.42lb/ft^3$ (specific weight of the water), and 0.85 for \eta

We need to figure the flow rate of the water (V) out, that is,

$V=\frac{P}{\gamma h \eta_0}$

Where $\eta_0$ is the turbine efficiency, at which is,

$\eta_0 = \frac{P}{\gamma Vh}$

Replacing,

$V=\frac{73.7*10^{3}}{62.42*400*0.85}$

$V=3.475ft^3/s$

With this value (the target of this question) we can also calculate the mass flow rate of the waters,

through the density and the flow rate,

$m=\rho V\\m= 3.475*1.94 \\m=6.7415 slugs/s$

converting the slugs to lbm, 1slug = 32.174lbm, we have that the mass flow rate of the water is,

$m= 217lbm/s$

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2 years ago

While operating a vehicle on any highway of this state, it is illegal to physically hold or support a wireless device with any p

algol13

Answer:

True

Explanation:

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3 years ago

What is the correct order of the steps in the scientific method

stira [4]

<h2>what is the correct order of the steps in the scientific method</h2>

Make a hypothesis, test the hypothesis, analyze the results, ask a question, draw conclusions, communicate results.

hope it helps

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2 years ago

TRUE or FALSE:

Aleksandr-060686 [28]

False. Both masses will experience an acceleration which depends on their mass. The small mass will experience a greater acceleration.

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