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FinnZ [79.3K]
3 years ago
13

Why does it seem that the Sun is rising and setting in the sky?

Physics
1 answer:
Anna [14]3 years ago
6 0
B when is spins it means its rotating east and west directions
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Calculate the potential difference if 20J of energy are transferred by 8C of charge.
grin007 [14]
<h2>v = 2.5J/c</h2>

Explanation:

<h2>Given:</h2>

<h3>Energy = E = 20J</h3>

<h3>Charge = Q = 8C</h3>

<h2>Require :</h2>

___________

<h3>Potential Difference = V = ?</h3>

<h2>Formula :</h2>

____________

<h2>V = \frac{E}{Q}</h2>

<h2>Solution:</h2><h3>_________</h3>

<h2>V = \frac{20J}{8C}</h2>

<h3>V = 2.5V</h3>

.

.

.

<h2>\color{Red}{Mark - Brainliest}</h2>
4 0
3 years ago
Please help!! The graph in the figure shows the position of a particle as it travels along the x-axis. What is the magnitude of
Bogdan [553]

Answer:

1.3 m/s

Explanation:

average speed = total distance/ total time

6 0
4 years ago
A car that experiences no frictional force is started and caused to move. For the car to continue in that motion, the gas pedal
Masteriza [31]

1) Answer D not at all

The car is not experiencing any frictional force so that implies that there is no force acting on the car once it starts motion. So, according law of inertia, the car will continue to move and no other force is required.

Friction force is the resistance force that opposes the motion of any object. It arises due to the contact of surfaces.

2) Answer C none

There is no force on any spaceship moving far from any planet. So, according to law of inertia the spacecraft will continue to move at same speed.

Law of inertia states that any object keeps in the state of motion or rest unless a non zero external force is applied on it.

6 0
3 years ago
Read 2 more answers
You pull a wagon with a force of 20 N. The wagon has a mass of 10 kg. What is the wagon's acceleration?
Nana76 [90]

Answer:

<h3>The answer is 2 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

where

f is the force

m is the mass

From the question

f = 20 N

m = 10 kg

We have

a =  \frac{20}{10}  \\

We have the final answer as

<h3>2 m/s²</h3>

Hope this helps you

5 0
3 years ago
(4A) The mass of Earth is 5.972 * 10^24 kg, and the radius of Earth is 6,371 km.
faltersainse [42]

Answer:

x₁ = 345100 km

Explanation:

The direction of the attraction forces between the earth and the object, and between the moon and the object, are in opposite direction and  (along the straight line between the centers of earth and moon) and as gravity is always attractive, the net force will become zero when both forces are equal. According to this:

Let  call "x₁"  distance between center of the earth and the object, and

"x₂" the distance between center of the moon and the object, Mt mass of the earth, Ml mass of the moon, m₀ mass of the object

we can express:

F₁  ( force between earth and the object )

F₁ = K *  Mt * m₀/ ( x₁)²        K is a gravitational constant

F₂  (force between mn and the object)

F₂ = K * Ml * m₀ / (x₂)²

Then:

F₁ = F₂               K*Mt*m₀ / x₁²   =  K*Ml*m₀ /x₂²

Or  simplifying the expression

Mt/ x₁²  =  Ml/ x₂²

We know that   x₁   +  x₂  = 384000 Km then

x₁ =  384000 - x₂

Mt/( 384000 - x₂)²  =  Ml / x₂²

Mt *  x₂²  =  Ml *( 384000 - x₂)²

We need to solve for x₂

Mt *  x₂²  =  Ml *[ ( 384000)² + x₂² - 768000*x₂]

By substitution:

5.972*10∧24*x₂² = 7.348*10∧22 * [ 1.47*10∧11 ] + 7.348*10∧22*x₂² -

                                7.348*10∧22*768000*x₂

Simplifying by 10∧22

5.972*10²*x₂²  = 7.348* [ 1.47*10∧11 ] + 7.348*x₂²- 7.348*768000*x₂

Sorting out

5.972*10²*x₂²- 7.348*x₂² = 10.80*10∧11 - 56,43* 10∧5*x₂

(597,2 - 7,348 )* x₂²  = 10.80*10∧11 - 56.43*10∧5*x₂

590x₂²  + 56.43*10∧5*x₂ - 10.80*10∧11 = 0

Is a second degree equation

x₂  =  -56.43*10∧5 ± √3184*10∧10 + 25488*10∧11  / 1160

x₂ ₁  = -56.43*10∧5 + √3184*10∧10 + 25488*10∧11  / 1160

x₂ ₁  =  -56.43*10∧5 + √3184*10∧10 + 254880*10∧10  / 1160

x₂ ₁  = -56.43*10∧5 + 10∧5 [ √3184 + 254880 ] /1160

x₂ ₁  =  -56.43*10∧5 + 508* 10∧5  / 1160

x₂ ₁  =  451.27*10∧5/1160

x₂ ₁  =  4512.7*10∧4 /1160

x₂ ₁  = 3.89*10∧4  km (distance between the moon  and the object)

x₂ ₁  = 38900 km

x₂ = 38900 km

We dismiss the other solution because is negative and there is not a negative distance

Then the distance between the earth and the object is:

x₁  = 384000 - x₂

x₁ = 384000 - 38900

x₁ = 345100 km

5 0
4 years ago
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