Answer:
6.03 mV
Explanation:
length of solenoid, L = 2 m, N = 12000, di/dt = 40 A/s,
Magnetic field due to solenoid
B = μ0 n i = μ0 N i / L
dB/dt = μ0 N / L x di / dt
dB /dt = (4 x 3.14 x 10^-7 x 12000 x 40) / 2 = 0.3 T/s
Induced emf, e = rate of change of magnetic flux
e = dΦ / dt = A x dB / dt
e = 3.14 x 0.08 x 0.08 x 0.3 = 6.03 x 10^-3 V = 6.03 mV
Answer:
Explanation:
1 ha = 10⁴ m²
1375 ha = 1375 x 10⁴ m² = 13.75 x 10⁶ m²
In flow in a month = .5 x 10⁶ x 30 m³ = 15 x 10⁶ m³
Net inflow after all loss = 18.5 - 9.5 - 2.5 cm = 6.5 cm = .065 m
Net inflow in volume = 13.75 x 10⁶ x .065 m³= .89375 x 10⁶ m³
Let Q be the withdrawal in m³
Q - 15 x 10⁶ - .89375 x 10⁶ = 13.75 x 10⁶ x .75 = 10.3125 x 10⁶
Q = 26.20 x 10⁶ m³
rate of withdrawal per second
= 26.20 x 10⁶ / 30 x 24 x 60 x 60
= 26.20 x 10⁶ / 2.592 x 10⁶
= 10.11 m³ / s
Answer: 0.53m
Explanation:
According to the equation of motion v²= v₀²+2as
Since the body is launched upward, the final velocity at the maximum height will be "zero" since the body will momentarily be at rest at the maximum height i.e v = 0
Initial velocity given (v₀) = 3.25 m/s
The body is also under the influence of gravity but the acceleration due to gravity will be negative being an upward force (a = -g) and the distance (s) will serve as our maximum height (h)
The equation of motion will.now become
V = v₀² -2gh
Where v = 0 v₀ = 3.25m/s g = 10m/s h = ?
0 = 3.25² - 2(10)h
0 = 10.56 - 20h
-10.56 = -20h
h = 10.56/20
h = 0.53m
Therefore, the maximum height, h (in meters), above the launch point that the basketball will achieve is 0.53m
Answer:
The final velocity 
Explanation:
Given data
Mass of merry go round 
= 120 kg
Radius = 1.8 m
Initial angular velocity 
= 0.6 
Mass of boy 
= 25 kg
We know that the final velocity is given by
Put all the values in above formula we get
This is the final velocity.
