1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vovangra [49]
3 years ago
11

Number of

Chemistry
1 answer:
zzz [600]3 years ago
6 0

Answer:

symbol= F

proton= 9

neutron= 19 I understand this is it ok for you

You might be interested in
Need help asap - There is an error in the rate-determining step of the following proposed mechanism.
sdas [7]

Answer:

CH4(g) + Cl2(g) → CH3(g) + HCl(g) and the rate rule is k1 = [CH4][Cl2]

Explanation:

Firstly, we must remember that the substitution reaction between halogens and alkanes to yield halogenoalkanes does not proceed by ionic mechanism rather it proceeds by free radical mechanism.

Now, if we look at the rate determining step as shown in the question, the elementary reaction equation of that step is not balanced.

Hence, the correct elementary reaction equation for the rate determining step and the rate law is; CH4(g) + Cl2(g) → CH3(g) + HCl(g) and the rate rule is k1 = [CH4][Cl2]

5 0
3 years ago
After measuring the mass of water, the data is averaged and it is determined that the mean of 4
gladu [14]

Answer:

2

Explanation:

8 0
3 years ago
Determine the partial negative charge on the bromine atom in a c−br bond. the bond length is 1.93 å and the bond dipole moment i
vaieri [72.5K]

Answer:

The value is x  =  0.151  \ e

Explanation:

From the question we are told that

The bond length is l  =  1.93\  \r  a =  1.93 *1 *10^{-10}  =1.93 *10^{-10}\  m

The bond dipole moment is \mu  = 1.40 d  = 1.40 *  3.33564 *10^{-30}  =  4.6699 *10^{-30} \  C \cdot m

Generally the dipole moment is mathematically represented as

\mu  =  Q *  l

Here Q is the partial negative charge on the bromine atom

So

Q =  \frac{\mu}{ l}

=> Q =  \frac{4.6699 *10^{-30}}{ 1.93 *10^{-10} }

=> Q = 2.42 *10^{-20} C

Generally

1 electronic charge(e) is equivalent to 1.60*10^{-19} C

So x electronic charge(e) is equivalent to Q = 2.42 *10^{-20} C

=> x  =  \frac{2.42 *10^{-20}}{1.60*10^{-19} }

=>     x  =  0.151  \ e

3 0
3 years ago
How many theoretical plates produce a chromatography peak eluting at 12.83 min with a width at half-height of 8.7 s
GrogVix [38]
Answer-Figure P38.63a
is a three-dimensional sketch of a birefringent crystal. The dotted lines illustrate how a thin, parallefaced slab of material could be cut from the larger specimen with the crystal’s optic axis parallel to the faces of the plate.”


Sorry if it’s it correct
4 0
3 years ago
Water, also known as H2O, cannot be separated into hydrogen and oxygen.
Dmitry [639]

Answer:

So, H2O means two atoms of hydrogen mixed with one atom of oxygen. All pure water is the same, two parts hydrogen to one part oxygen. ... Water cannot be separated by any physical means.

Explanation:

Logic and my notes from chem....

6 0
3 years ago
Read 2 more answers
Other questions:
  • AS a solid substance absorbs heat at its melting point, the melting point will
    7·1 answer
  • Using ankle weights when running or walking does what
    10·1 answer
  • What is a observation?
    10·2 answers
  • Explain why the speed of sound is faster in solids than in gases. Include two other factors Chapter 17 says the speed of sound c
    11·2 answers
  • Which two polymers have glucose monomers?
    6·1 answer
  • The natural abundances of the two stable isotopes of hydrogen (hydrogen and deuterium) are 99.99 percent and 0.01 percent. Assum
    12·1 answer
  • Determine the solution of 8x + 4y = 12 and y= -2x + 3
    6·1 answer
  • Mention the four characterstics of warm blooded animals.<br>​
    15·2 answers
  • You are using your hot air balloon to travel. At constant pressure, you decrease the temperature of the gas by turning down the
    12·1 answer
  • Help! awarding 20 points ​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!