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3 years ago

In the following equation, what are the reactants: NaHCO3 + HCl? NaCl + H2O + CO2

2 answers:

6 0

I believe the correct answer from the choices listed above is option A. The reactant for the given chemical reaction would be NaHCO3 and HCl. A reactant is a substance that changes in a chemical reaction. It is the starting material in a reaction. Hope this answers the question.

BARSIC [14]3 years ago

6 0

NaHCO3, HCl is the answer for sure

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Which of the following is an extensive property of a sample of aluminum?

levacccp [35]

Answer:

Entropy,mass and volume.... I think

5 0

3 years ago

Identify the oxidized substance, the reduced substance, the oxidizing agent, and the reducing agent in the redox reaction. Cu(s)

spin [16.1K]

Answer: Copper is getting oxidized and is a reducing agent. Silver is getting reduced and is oxidizing agent.

Explanation:

Oxidation reaction is defined as the reaction in which an atom looses its electrons. Here, oxidation state of the atom increases.

$X\rightarrow X^{n+}+ne^-$

Reduction reaction is defined as the reaction in which an atom gains electrons. Here, the oxidation state of the atom decreases.

$X^{n+}+ne^-\rightarrow X$

Oxidizing agents are defined as the agents which oxidize other substance and itself gets reduced. These agents undergoes reduction reactions.

Reducing agents are defined as the agents which reduces the other substance and itself gets oxidized. These agents undergoes reduction reactions.

For the given chemical reaction:

$Cu(s)+2AgNO_3(aq.)\rightarrow 2Ag(s)+Cu(NO_3)_2(aq.)$

The half reactions for the above reaction are:

Oxidation half reaction: $Cu(s)\rightarrow Cu^{2+}(aq.)+2e^-$

Reduction half reaction: $2Ag^+(aq.)+2e^-\rightarrow 2Ag(s)$

From the above reactions, copper is loosing its electrons. Thus, it is getting oxidized and is considered as a reducing agent.

Silver is gaining electrons and thus is getting reduced and is considered as an oxidizing agent.

4 0

4 years ago

What atomic or hybrid orbitals make up the sigma bond between c2 and c3 in propyne, chcch3 ? (c2 is the second carbon in the str

Anvisha [2.4K]

Answer:

$\boxed{\text{$\sigma$(sp-sp$^{3}$); 180$^{\circ}$}}$

Explanation:

(a) Hybridization of orbitals

See the Lewis structure of propyne in the first diagram below.

C1 is directly bonded to two other atoms (H and C2) so it is sp hybridized.

C2 is directly bonded to two other atoms (C1 and C3) so it is sp hybridized.

C3 is directly bonded to four other atoms (C2 and 3 H) so it is sp³ hybridized.

(b) C2-C3 Sigma Bond

See the atomic and molecular orbitals in the second picture below.

C3 is using its hybrid atomic orbitals to form sigma molecular bonds. The C2-C3 sigma bond is formed by the overlap of the C2 sp atomic orbital with the C3 sp³ atomic orbital to make a σ(sp-sp³) molecular orbital.

C1 and C2 are sp hybridized. Since the angle between sp orbitals is 180°, all atoms directly attached the C1 and C2 must be in a straight line. The C-C-C bond angle is 180°.

4 0

3 years ago

SO2(g)+NaOH(s)=Na2SO3(s)+H2O

Lisa [10]

Explanation:

SO2 + 2NaOH → Na2SO3 + H2O

 $...$ 

6 0

4 years ago

Which factors can affect the amount of coco mix that can be dissolved in water? Check all that apply

elixir [45]

Answer:

1) adding ice

2) adding heat

3) altering amount of water

4) using a different kind of cocoa mix

Explanation:

Dissolution of a substance in another can be affected by temperature changes, concentration and the type of mix we are using.

The higher the temperature, the more readily a compound will dissolve in another. The rate of dissolution of a solute in a solvent is affected by prevailing temperature at hand.

The more the water which is the solvent, the more the solute that can be dissolved in it. Reaction rate is directly proportional to concentration.

A different cocoa mix might dissolve better in this case also.

5 0

3 years ago