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kirill [66]
2 years ago
15

If I have 2 mol NaOH in 3 L of solution, what is the molarity of my solution?

Chemistry
1 answer:
qwelly [4]2 years ago
3 0

Answer:

0.67 mole/litre

Explanation:

the molarity equall no. of moles ÷ volume of sol.

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Andrei [34K]

demonstrates the formation of a solid precipitate

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3 years ago
A river with a flow of 50 m3/s discharges into a lake with a volume of 15,000,000 m3. The river has a background pollutant conce
spin [16.1K]

Explanation:

The given data is as follows.

       Volume of lake = 15 \times 10^{6} m^{3} = 15 \times 10^{6} m^{3} \times \frac{10^{3} liter}{1 m^{3}}

        Concentration of lake = 5.6 mg/l

Total amount of pollutant present in lake = 5.6 \times 15 \times 10^{9} mg

                                                                    = 84 \times 10^{9} mg

                                                                    = 84 \times 10^{3} kg

Flow rate of river is 50 m^{3} sec^{-1}

Volume of water in 1 day = 50 \times 10^{3} \times 86400 liter

                                          = 432 \times 10^{7} liter

Concentration of river is calculated as 5.6 mg/l. Total amount of pollutants present in the lake are 2.9792 \times 10^{10} mg or 2.9792 \times 10^{4} kg

Flow rate of sewage = 0.7 m^{3} sec^{-1}

Volume of sewage water in 1 day = 6048 \times 10^{4} liter

Concentration of sewage = 300 mg/L

Total amount of pollutants = 1.8144 \times 10^{10} mg or 1.8144 \times 10^{4}kg

Therefore, total concentration of lake after 1 day = \frac{131936 \times 10^{6}}{1.938 \times 10^{10}}mg/ l

                                        = 6.8078 mg/l

                 k_{D} = 0.2 per day

       L_{o} = 6.8078

Hence, L_{liquid} = L_{o}(1 - e^{-k_{D}t}

             L_{liquid} = 6.8078 (1 - e^{-0.2 \times 1})  

                             = 1.234 mg/l

Hence, the remaining concentration = (6.8078 - 1.234) mg/l

                                                             = 5.6 mg/l

Thus, we can conclude that concentration leaving the lake one day after the pollutant is added is 5.6 mg/l.

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3 years ago
What is the relationship between metals and the number of electrons in the outer level?
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Elements in group 1-2, 13-18, the number of valence electrons is related to the group number. For example, in the first group, the alkali metals there is one valence electron, however in group 13, there are 3 valence electrons. Valence electrons are also known as the outershell electrons.
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2 years ago
Several science students were about to conduct an experiment on electricity. The teacher passed on the science activity which cl
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C. You should ALWAYS ask the teacher if you don't get something; your friends could be wrong, don't guess it, and NEVER cheat. Hope this helps!!
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2 years ago
Which phrases describe clastic sedimentary rocks? Check all that apply.
Romashka [77]

Explanation:

A clastic sedimentary rock is a rock that is formed from pre-existing rock materials and minerals. This materials have been transported to their new positions by the agents of denudation.

  1. Clastic sedimentary rocks are made up of rock fragments predominantly.
  2. The matrix is usually remnants of other rocks.
  3. A cementing material can form between clasts and holds them in place. Cements are usually iron oxides, calcite e.t.c.
  4. These rock types are usually formed from mechanincal weathering of rocks
  5. Mechanical weathering breaks down rocks into chunks.
  6. Examples are breccia, conglomerates, e.t.c.

Learn more:

Sedimentary rocks brainly.com/question/2740663

#learnwithBrainly

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