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joja [24]
3 years ago
11

A speed-time graph is shown below:

Physics
1 answer:
alexandr1967 [171]3 years ago
3 0

Answer:

<em>The average acceleration of the object is 0.5 cm/s^2</em>. Answer: A)

Explanation:

<u>Average Acceleration</u>

The average acceleration of a moving object is the rate at which the speed changed over time in a specific period. It can be calculated as follows:

\displaystyle \bar a=\frac{v_f-v_o}{t}

Where vf is the final speed, vo is the initial speed and t is the time.

The speed-time shows the speed starts at 0 cm/s and ends at 4 cm/s over the 8 seconds period. The average acceleration is:

\displaystyle \bar a=\frac{4-0}{8}=0.5

The average acceleration is 0.5 cm/s^2

A) Correct. The average acceleration is 0.5 cm/s^2

B) Incorrect. The average acceleration is 0.5 cm/s^2

C) Incorrect. The average acceleration is 0.5 cm/s^2

D) Incorrect. The average acceleration is 0.5 cm/s^2

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What happens to the position of an object as an unbalanced force acts on?
jarptica [38.1K]

Answer:

Unbalanced forces change the motion of an object. If an object is at rest and an unbalanced force pushes or pulls the object, it will move. Unbalanced forces can also change the speed or direction of an object that is already in motion.

5 0
3 years ago
Read 2 more answers
10. Mario is making chocolate. In part of the chocolate-making process, he changed the phase from a liquid to a solid. What happ
Naily [24]

Answer:

B

Explanation:

in a liquid the particles are widespread and move around each other but in a solid they move in place and are tightly packed

6 0
3 years ago
Imagine you're standing on a skateboard and your friend pushes you to the left with a force of 100 N. Neglecting friction and ai
ArbitrLikvidat [17]
It might be pull at a force of 100 N. I might be wrong.
6 0
3 years ago
A total electric charge of 6.75 nC is distributed uniformly over the surface of a metal sphere with radius 20.0 cm. If the poten
djverab [1.8K]

Answer:

a) 60 V

b) 125 V

c) 125 V

Explanation:

<u>Given</u>

We are given the total electric charge q = 6.75 nC = 6.75x 10^-9 C distributed uniformly over the surface of a metal sphere with a radius of R = 20.0 cm = 0.020 m.  

<u>Required </u>

We are asked to calculate the potential at the distances

(a) r = 10.0 cm

(b) r = 20.0 cm

(c) r = 40.0 cm  

<u>Solution</u>

(a) Here, the distance r > R so, we can get the potential outside the sphere (r > R) where the potential is given by

V = q/4\pi∈_o                       (1)

r is the distance where the potential is measured and the term 1/4\pi∈_o equals  9.0 x 10^9 Nm^2/C^2. Now we can plug our values for q and r into equation (1) to get the potential V where r = 0.10 m  

V= 1*q/4\pi∈_o*r

 =60 V

(b) Here the distance r is the same for the radius R, so we can get the potential inside the sphere (r = R) where the potential is given by  

V = 1*q/4\pi∈_o*R                (2)    

Now we can plug our values for q and R into equation (2) to get the potential V where R = 0.20 m  

V = 1*q/4\pi∈_o*R

    = 125 V

(c) Inside the sphere the electric field is zero therefore, no work is done on a test charge that moves from any point to any other point inside the sphere. Thus the potential is the same at every point inside the sphere and is equal to the potential on the surface. and it will be the same as in part (b)  

V= 125 V

7 0
3 years ago
The dimensions of aluminum foil in a box for sale in super markets are 66 2/3 yards by 12 inches. the mass of the foil is 0.83 k
disa [49]

Length of the sheet is given as

L = \frac{200}{3} yards = 6096 cm

width of the sheet is given as

w = 12 inches = 30.48 cm

now let say its thickness is "t"

so the volume of the sheet is given as

V = L*w*t

V = 6096*30.48* t

V = 185806.08*t cm^3

mass of the sheet is given as

m = 0.83 kg = 830 gram

now we have

density = \frac{mass}{volume}

2.70 = \frac{830}{185806.08*t}

by solving above we have

t = 1.65 * 10^{-3} cm

so the thickness of sheet will be above

4 0
3 years ago
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