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2 years ago

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The magnetic field of the brain has been measured to be approximately 3.0×10−12T. Although the currents that cause this field ar

e quite complicated, we can get a rough estimate of their size by modeling them as a single circular current loop 16 cm (the width of a typical head) in diameter. What current is needed to produce such a field at the center of the loop?

1 answer:

saw5 [17]2 years ago

7 0

Answer:

I = 3.82 x 10^(−7) A

Explanation:

The formula for magnetic field at the centre of a loop is given as;

B = μI/2R

Where μ is a magnetic constant with a value of 12.57 × 10^(−7) H/m.

I = current

R = Radius = 16/2 = 8cm or 0.08m

B = 3.0×10^(−12) T

So making I the subject of the formula, we obtain ;

I = 2RB/μ

Thus, I = [2 x 0.08 x 3.0×10^(−12)]/12.57 × 10^(−7)

I = 3.82 x 10^(−7) A

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10. How far does a transverse pulse travel in 1.23 ms on a string with a density of 5.47 × 10−3 kg/m under tension of 47.8 ?????

KATRIN_1 [288]

Answer: Tension = 47.8N, Δx = 11.5× $10^{-6}$ m.

Tension = 95.6N, Δx = 15.4× $10^{-5}$ m

Explanation: A speed of wave on a string under a tension force can be calculated as:

$|v| = \sqrt{\frac{F_{T}}{\mu} }$

$F_{T}$ is tension force (N)

μ is linear density (kg/m)

Determining velocity:

$|v| = \sqrt{\frac{47.8}{5.47.10^{-3}} }$

$|v| = \sqrt{0.00874 }$

$|v| =$ 0.0935 m/s

The displacement a pulse traveled in 1.23ms:

$\Delta x = |v|.t$

$\Delta x = 9.35.10^{-2}*1.23.10^{-3}$

Δx = 11.5× $10^{-6}$

With tension of 47.8N, a pulse will travel Δx = 11.5× $10^{-6}$ m.

Doubling Tension:

$|v| = \sqrt{\frac{2*47.8}{5.47.10^{-3}} }$

$|v| = \sqrt{2.0.00874 }$

$|v| = \sqrt{0.01568}$

|v| = 0.1252 m/s

Displacement for same time:

$\Delta x = |v|.t$

$\Delta x = 12.52.10^{-2}*1.23.10^{-3}$

$\Delta x =$ 15.4× $10^{-5}$

With doubled tension, it travels $\Delta x =$ 15.4× $10^{-5}$ m

4 0

3 years ago

You then measure Polly's internal temperature to be 13oC, which is quite a drop from the normal human body temperature of 37oC.

ankoles [38]

Answer:

The specific heat is 3.47222 J/kg°C.

Explanation:

Given that,

Temperature = 13°C

Temperature = 37°C

Mass = 60 Kg

Energy = 5000 J

We need to calculate the specific heat

Using formula of energy

$Q= mc\Delta T$

$c =\dfrac{Q}{m\Delta T}$

Put the value into the formula

$c=\dfrac{5000}{60\times(37-13)}$

$c=3.47222\ J/kg^{\circ}C$

Hence, The specific heat is 3.47222 J/kg°C.

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3 years ago

What does Newton's law all about?<br>

KengaRu [80]

Newton's law is all about motion

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2 years ago

Lightning can sometimes occur on hot and humid summer evenings when there are no thunderstorms.

mart [117]

Answer:

(B) False

Explanation:

No, it is not possible to have thunder without lightning. Thunder is a direct result of lightning.

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3 years ago

Read 2 more answers

She leaves her campsite and runs north for 10 miles turns east and runs 8 miles then turns south and runs 2 miles.whats her dist

Mama L [17]

The distance is 20 miles

Explanation:

Definitions:

Distance is the total length of the path covered by an object during its motion, regardless of the direction of its motion
Displacement is the shortest distance between the initial and final position of the motion, so it also takes into account the direction of motion

In this problem, we want to know the distance covered by the woman. The motion consists of the following parts:

$d_1 = 10 miles$ north

$d_2 = 8 miles$ east

$d_3 = 2 miles$ south

To find the distance, we just have to add the length of each path, ignoring the direction. Therefore:

$d=d_1 + d_2 + d_3 = 10+8+2 = 20 miles$

Learn more about distance and displacement:

brainly.com/question/3969582

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3 years ago