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3 years ago

Un compuesto ZO2 tiene masa molar igual a 64. La masa atómica de Z debe ser: A . 6. C. 12. E. 32. B. 10. D. 24.

Chemistry

1 answer:

9966 [12]3 years ago

7 0

Answer:

32. Opcion E

Explanation:

ZO₂ podemos entenderlo como dióxido de Z

1 mol de ZO₂ contiene 1 mol de Z y 2 moles de O₂ por lo que si la masa molar es de 64 g/mol, podemos plantear lo siguiente

Masa de Z + 2 masa de O = 64 g/mol

Sabemos que la masa del oxígeno es 16 g/mol

x + 2. 16 g/mol = 64 g/mol

x = 64 - 32 → 32 g/mol

La masa atómica coincide con la masa molar, por lo tanto la masa atomica de Z es 32.

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3 years ago

An aqueous CsCl solution is 8.00 wt% CsCl and has a density of 1.0643 g/mL at 20°C. What is the boiling point of this solution?

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<u>Answer:</u> The boiling point of solution is 100.53

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8.00 wt % of CsCl

This means that 8.00 grams of CsCl is present in 100 grams of solution

Mass of solvent = (100 - 8) g = 92 grams

The equation used to calculate elevation in boiling point follows:

$\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}$

To calculate the elevation in boiling point, we use the equation:

$\Delta T_b=iK_bm$

Or,

$\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}$

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i = Vant hoff factor = 2 (For CsCl)

$K_b$ = molal boiling point elevation constant = 0.51°C/m

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$W_{solvent}$ = Mass of solvent (water) = 92 g

Putting values in above equation, we get:

$\text{Boiling point of solution}-100=2\times 0.51^oC/m\times \frac{8.00\times 1000}{168.4g/mol\times 92}\\\\\text{Boiling point of solution}=100.53^oC$

Hence, the boiling point of solution is 100.53

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