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3 years ago

How many molecules of water or in 1 liter (56 mol)?

Chemistry

1 answer:

dem82 [27]3 years ago

6 0

1 mol of any particles = 6.02*10²³ particles

56 mol*6.02*10²³ molecules of water/1 mol =3.37*10²⁵

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Which element would be the least similar to magnesium (Mg)?<br> A. Sr<br> B. Na<br> C. Be<br> D. Ca

Alika [10]

Answer:

B: NA

Explanation:

this is the apex answer

3 0

3 years ago

What are the units of k in the following rate law?

Ludmilka [50]

Answer:

B. $\frac{1}{M^{2} s }$

Explanation:

The unit for rate is M/s while the unit for each molecule should be M. You can find the unit for k by putting the units for rate and the molecules into the equation

rate= k{X][Y]

M/s= k * $M^{2}$ * $M^{1}$

k= (M/s) / ( $M^{3}$ )

k= $\frac{1}{M^{2} s }$

You can also use this predetermined formula to solve this problem faster: k= $\frac{M^{1-n} }{s }$

Where n is the number of molecule. There are 3 molecule(2X and 1Y) so n=3, so

k= $\frac{M^{1-n} }{s }$

k= $\frac{M^{1-3} }{s }$ = $\frac{m^{-2}}{s}$ = $\frac{1}{M^{2} s }$

8 0

4 years ago

Find the total surface area of the rectangular prism in the figure. A) 174 cm^ 2 B) 522c * m ^ 2; 348c * m ^ 2 D) 432c * m ^ 2

WARRIOR [948]

Surface area: 348 m^2

8 0

2 years ago

Read 2 more answers

How many moles of CCI are there in 78.2 g of CCI.?

vaieri [72.5K]

Answer:

0.508 mole

Explanation:

NOTE: Since no hydrogen is attached to the compound given in question above, it means the compound is CCl₄.

The number of mole present in 78.2 g of CCl₄ can be obtained as follow:

Mass of CCl₄ = 78.2 g

Molar mass of CCl₄ = 12 + (35.5×4)

= 12 + 142

= 154 g/mol

Mole of CCl₄ =?

Mole = mass / molar mass

Mole of CCl₄ = 78.2 / 154

Mole of CCl₄ = 0.508 mole

Therefore, 0.508 mole is present in 78.2 g of CCl₄

6 0

3 years ago

What is the density of an object that has a volume of 34.2 cm^3 and a mass of 19.6 g? (a) 0.573 g/cm^3 (b) 1.74 g/cm^3 (c) 670 g

KengaRu [80]

Answer: The density of the object will be $0.573g/cm^3$

Explanation:

Density is defined as the mass contained per unit volume.

$Density=\frac{mass}{Volume}$

Given : Mass of object = 19.6 grams

Volume of object= $34.2cm^3$

Putting in the values we get:

$Density=\frac{19.6g}{34.2cm^3}=0.573g/cm^3$

Thus density of the object will be $0.573g/cm^3$

8 0

4 years ago