Given that the rope is not moving (acceleration is zero), by the second Law of Newton (F=m*a), the net force acting on the rope is zero.
Then, the force applied by the team B equals the force applied by the tema A: 103 N.
Answer: Carbon 14 and Uranium 238 are not used together to determine fossil ages.
Explanation:
Carbon 14 with a half life of 5,700 years can only be used to date fossils of approximately 50,000 years. Most fossils are thought to be much older than 50,000 years. Also most fossils no longer contain any Carbon. The fossilized remains have been mineralized where the original organic material has been replaced and turned into stones containing no carbon.
Uranium 238 has a half life of 4.5 billion years. Uranium can be used to date the age of the earth. If 50% of pure uranium' is left in a sample the sample is assumed to be 4.5 billion years old.( This is assuming that the original sample was 100% uranium and no Uranium 238 has been eroded or lost in 4.5 billion years old. If a fossil has only 25 % of the Uranium 238 the sample has an estimated age of 3.2 Billion years. This would be the estimated age of the earliest life or formation of fossils.
Note no fossils contain Uranium 238. Uranium 238 is only found in igneous or volcanic rocks. So no fossils can be dated directly using U 238.
Because of the huge differences in the half lives of Carbon 14 and Uranium238 they cannot be used together. Carbon 14 can only be used to date fossils of a very recent age. Uranium 238 can only be used to date volcanic rocks of a very old age.
Answer:
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Explanation:
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Answer:
a) x component = -31.25 km/hr
b) y component = 46.64 km/hr
Explanation:
Given data:
A position is 4km north and 2.5 km east to B
Ship A velocity = 22 km/hr
ship B velocity = 40 km/hr
A velocity wrt to velocity of B
putting respective value to get velocity of A with respect to B
a) x component = -31.25 km/hr
b) y component = 46.64 km/hr
@AL2006 had answered this before: Well, first of all, wherever you got this question from has done
a really poor job of question-writing. There are a few assorted
blunders in the question, both major and minor ones:
-- 22,500 is the altitude of a geosynchronous orbit in miles, not km.
-- That figure of 22,500 miles is its altitude above the surface,
not its radius from the center of the Earth.
-- The orbital period of a synchronous satellite has to match
the period of the Earth's rotation, and that's NOT 24 hours.
It's about 3 minutes 56 seconds less ... about 86,164 seconds.
Here's my solution to the question, using some of the wreckage
as it's given, and correcting some of it. If you turn in these answers
as homework, they'll be marked wrong, and you'll need to explain
where they came from. If that happens, well, serves ya right for
turning in somebody else's answers for homework.
The satellite is traveling a circle. The circle's radius is 26,200 miles
(not kilometers) from the center of the Earth, so its circumference
is (2 pi) x (26,200 miles) = about 164,619 miles.
Average speed = (distance covered) / (time to cover the distance)
= (164,619 miles) / day
(264,929 km)
= 6,859 miles per hour
(11,039 km)
= 1.91 miles per second
(3.07 km)
