Answer:
<u><em>When sunlight shines through an orange solution, the violet, blue and green wavelengths are absorbed.</em></u> The other colors pass through.
Answer:
They can't hear an echo in small room because in it the sound can't be reflected back. For an echo of a sound to be heard,the minimum distance between the source of sound and the walls of the room should be 17.2 m.
hopw it helps
Answer:
B) False.
Explanation:
Most of the times, the numbers that appears right to the cursor are representing the coordinates (x & y) of the cursor. So as the cursor moves around the screen those number changes accordingly.Therefore its wrong to say that there is no need to add a dimension to set the dimensional value.
Answer:
58.27 N
Explanation:
the data we have is:
mass: 
coefficient of friction: 
and we also know the acceleration of gravity is 
We need to do an analysis of horizontal and vertical forces acting on the object:
-------
Vertically the forces acting on the object:
- Normal force
(acting up from the object)
- weight:
(acting down from)
so the sum of forces in the vertical axis "y" are:

from Newton's second Law we know that
, so:

and since the object is not accelerating in the vertical direction (the movement is only horizontal)
, and:

-----------
now let's analyze the horizontal forces
- frictional force:
and since
--> 
- force to move the object:

and the two forces just mentioned must be opposite, thus the sum of forces in the "x" axis is:

and we are told that the crate moves at a steady speed, thus there is no acceleration: 
and we get:

substituting known values:

Answer: 33 mm
Explanation:
Given
Diameter of the tank, d = 9 m, so that, radius = d/2 = 9/2 = 4.5 m
Internal pressure of gas, P(i) = 1.5 MPa
Yield strength of steel, P(y) = 340 MPa
Factor of safety = 0.3
Allowable stress = 340 * 0.3 = 102 MPa
σ = pr / 2t, where
σ = allowable stress
p = internal pressure
r = radius of the tank
t = minimum wall thickness
t = pr / 2σ
t = 1.5*10^6 * 4.5 / 2 * 102*10^6
t = 0.033 m
t = 33 mm
The minimum thickness of the wall required is therefore, 33 mm