1.4715 atm is the pressure of the sample 1.33 moles of fluorine gas that is contained in a 23.3 L container at 314 K.
What is an ideal equation?
The ideal gas equation, pV = nRT, is an equation used to calculate either the pressure, volume, temperature or number of moles of a gas. The terms are: p = pressure, in pascals (Pa).
Given data:
Volume (V) = 23.3 L
Number of mole (n) = 1.33 moles
Temperature (T) = 314 K
Gas constant (R) = 0.821 atm.L/Kmol
Pressure (P) =?
The pressure inside the container can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
P × 23.3 L = 1.33 moles × 0.0821 ×314 K
P = 1.4715 atm
Therefore, the pressure of the sample is 1.4715 atm.
Learn more about the ideal gas equation:
brainly.com/question/23826793
SPJ1
Answer:
Hi there!
The answer to this question is: True
Atoms make up an element
I would i have think it is either a) east or c) west b/c couldn’t go by it self
Answer:
7.38 g/cm³ is the density of the metal
Explanation:
In a Face-centered cubic unit cell you have 4 atoms. Also, the edge length is √8×r (r is radius of the atom).
To solve this problem, we need first to calculate the volume of the unit cell and then, with molar mass calculate the mass of 4 atoms. As density is the ratio between mass and volume we can obtain this value.
- <em>Volume of the unit cell</em>
Volume = a³
a = √8×r
(r = 198x10⁻¹²m)
a = 5.6x10⁻¹⁰ m
Volume = 1.756x10⁻²⁸ m³
1m = 100cm → 1m³ = (100cm)³:
1.756x10⁻²⁸ m³× ((100cm)³ / 1m³) =
<h3> 1.756x10⁻²² cm³ → Volume of the unit cell in cm³</h3><h3 />
- <em>Mass of the unit cell:</em>
<em>There are 4 atoms of gold:</em>
4 atoms × (1mol / 6.022x10²³ atoms) = 6.64x10⁻²⁴ moles of gold
As 1 mole weighs 195.08g:
6.64x10⁻²⁴ moles of gold × (195.08g / mol) =
<h3>1.296x10⁻²¹g is the mass of the unit cell</h3><h3 />
- <em>Density of the metal:</em>
1.296x10⁻²¹g / 1.756x10⁻²² cm³ =
<h3>7.38 g/cm³ is the density of the metal</h3>
