Body temperature is controlled by a negative feedback control system.
What is negative feedback?
In biological systems, a type of control known as negative feedback occurs when a process's output lowers its own stimulus. A common regulation mechanism in many biological responses is feedback. The body may regulate numerous aspects of its internal environment by permitting particular routes to be switched on and off. This is like turning a switch. Feedback enables a pathway's output to operate a switch. Negative feedback, often known as a "negative feedback loop," happens when a pathway's end product disables the corresponding metabolic step.
In order to maintain body temperature, the hypothalamus reacts to this information by directing nerve impulses to effectors. For instance, the hair erector muscles tighten up if we get too cold. As a result, a layer of air is trapped near to the skin, raising the skin hairs. Systematic negative feedback regulates body temperature.
<u>Thus the </u><u>hypothalamus</u><u> is the vital organ for this system.</u>
To learn more about negative feedback from the given link below,
brainly.com/question/11525272
#SPJ4
Answer:
Approximately 53.3 %.
Explanation:
Molar mass of C2H4O2
= 2 * 12.011 + 4 * 1.008 + 2 * 15.999
= 60.052
% oxygen = (31.998* 100) / 60.052 = 53.28 %
<h3>Answer:</h3>
The two possible compounds are;
1) Dimethyl Ether H₃C--O--CH₃
2) Ethanol H₃C--CH₂--OH
<h3>Solution:</h3>
Step 1: Calculate Moles of each Element;
Moles of C = %C ÷ At.Mass of C
Moles of C = 52.14 ÷ 12.01
Moles of C = 4.341 mol
Moles of H = %H ÷ At.Mass of H
Moles of H = 13.13 ÷ 1.01
Moles of H = 13.00 mol
Moles of O = %O ÷ At.Mass of O
Moles of O = 34.73 ÷ 16.0
Moles of O = 2.170 mol
Step 2: Find out mole ratio and simplify it;
C H O
4.341 13.00 2.170
4.341/2.170 13.00/2.170 2.170/2.170
2 5.99 1
2 6 1
Hence, Empirical Formula = C₂H₆O
<h3>Result:</h3>
As the molecular mass of compound is not given therefore, we can assume and guess the empirical formula to be the molecular formula. Hence, possible compounds are,
1) Dimethyl Ether H₃C--O--CH₃
2) Ethanol H₃C--CH₂--OH
The question is missing a part, so the complete question is as follows:
The protein catalase catalyzes the reaction The Malcolm Bladrigde National Quality Awards aims to: 2H2O2 (aq) ⟶ 2H2O (l) + O2 (g) and has a Michaelis-Menten constant of KM = 25mM and a turnover number of 4.0 × 10 7 s -1. The total enzyme concentration is 0.012 μM and the intial substrate concentration is 5.14 μM. Catalase has a single active site. Calculate the value of Rmax (often written as Vmax) for this enzyme. Calculate the initial rate, R (often written as V0), of this reaction.
1) Calculate Rmax
The turnover number (Kcat) is a ratio of how many molecules of substrate can be converted into product per catalytic site of a given concentration of enzyme per unit of time:
Kcat = 
,
where:
Vmax is maximum rate of reaction when all the enzyme sites are saturated with substrate
Et is total enzyme concentration or concentration of total enzyme catalytic sites.
Calculating:
Kcat =
Vmax = Kcat · Et
Vmax = 4×
· 1.2 × 
Vmax = 4.8 × 
M
2) Calculate the initial rate of this reaction (R):
The Michaelis-Menten equation studies the dynamics of an enzymatic reaction. This model can explain how an enzyme enhances the rate of a reaction and how the reaction rate depends on the concentration of the enzyme and its substrate. The equation is:
V0 = ![\frac{[S].(Vmax)}{KM + [S]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BS%5D.%28Vmax%29%7D%7BKM%20%2B%20%5BS%5D%7D)
, where:
[S] is the substrate's concentration
KM is the Michaelis-Menten constant
Substituting [S] = 5.14 × 
, KM = 2.5 × 
and Vmax = 4.8 × , the result is V0 = 0.478 M.
The answers are Vmax = 4.8 × M and V0 = 0.478 M.
Answer:
What is the empirical formula of the compound?
Explanation:
When the relative masses of elements in a hydrocarbon are given, it is possible to use this information to obtain the empirical formula by dividing the given masses of each element by the relative atomic masses of the element. The lowest ratio is now used to divide through to obtain the empirical formula of the compound.
The empirical formula only shows that ratio of atoms of each element present in the compound. From the information provided, the empirical formula of the compound is CH2. Hence the answer.
