Gravity pulls on the object in the downward direction. The normal force to the inclined plane points in a direction perpendicular to the surface of the plane. Then for the object to be at rest, the frictional force must act parallel to the inclined plane, pointing in the upward direction.
speed of the car at t = 10 s is given as 10 m/s
now at t = 30 s car comes to rest so v = 0
now in this velocity time graph we can say slope will show the acceleration of the car as we know that acceleration is rate of change in velocity

as we know that



now from above formula

So slope of the graph will represent the acceleration of car which is 0.5 m/s^2
Answer:
pf = 198.8 kg*m/s
θ = 46.8º N of E.
Explanation:
- Since total momentum is conserved, and momentum is a vector, the components of the momentum along two axes perpendicular each other must be conserved too.
- If we call the positive x- axis to the W-E direction, and the positive y-axis to the S-N direction, we can write the following equation for the initial momentum along the x-axis:

- We can do exactly the same for the initial momentum along the y-axis:

- The final momentum along the x-axis, since the collision is inelastic and both objects stick together after the collision, can be written as follows:

- We can repeat the process for the y-axis, as follows:

- Since (1) is equal to (3), replacing for the givens, and since p₀Bₓ = 0, we can solve for vfₓ as follows:

- In the same way, we can find the component of the final momentum along the y-axis, as follows:

- With the values of vfx and vfy, we can find the magnitude of the final speed of the two-object system, applying the Pythagorean Theorem, as follows:

- The magnitude of the final total momentum is just the product of the combined mass of both objects times the magnitude of the final speed:

- Finally, the angle that the final momentum vector makes with the positive x-axis, is the same that the final velocity vector makes with it.
- We can find this angle applying the definition of tangent of an angle, as follows:

⇒ θ = tg⁻¹ (1.06) = 46.8º N of E
Answer:
none
Explanation:
it's to high up to be affected by the gravity
1h----------------> 70x3=210 bacteria
2h-----------------> 210*3=630 bactaeria
let be y the number of bacteria at the t=0h
it is y=70 3^0
for t= 1h
y=70*3^1=210
for t=2h
y=70*3^2=630
so we can write y=70*3^x, where x is the number of hour