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Katena32 [7]
3 years ago
14

Light from a 600 nm source goes through two slits 0.080 mm apart. What is the angular separation of the two first order maxima o

ccurring on a screen 2.0 m from the slits
Physics
1 answer:
Vera_Pavlovna [14]3 years ago
6 0

Answer:

The angular separation is  k  =  0.8594^o

Explanation:

From the question we are told that

   The  wavelength of the light is \lambda  =  600 \ nm  =  600*10^{-9} \  m

   The  distance of separation between the slit is  d =  0.080 \ mm  =  0.080 *10^{-3} \  m

    The distance from the screen is

Generally the condition for  constructive interference is mathematically represented as

        d \ sin(\theta) =  n \lambda

=>    \theta =  sin ^{-1} [ \frac{n *  \lambda }{ d } ]

    here \theta is the angular separation between the central maxima and one side of the first order maxima

given that we are considering the first order of maxima n =  1  

        =>   \theta =  sin ^{-1} [ \frac{1  *  600*10^{-9} }{  2.0 } ]

        =>    \theta =  sin ^{-1} [ 0.0075 ]

        =>   \theta =  0.4297^o

So the angular separation of the two first order maxima  is  

     k  =  2 *  \theta

     k  =  2 *  0.4297

      k  =  0.8594^o

           

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When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees
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Answer:

a)  F = 1.26 10⁵ N,  b)  F = 2.255 10³ N, c)   F_ {soil} = 3078 N

Explanation:

For this exercise we will use the relationship between momentum and moment

          I = Δp

          F t = p_f -p₀

a) with stiff legs, final speed is zero, initial velocity is down

         Ft = 0-p₀

         F =  m v / t

let's calculate

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b) bending the legs

         

let's calculate

         F = 84.0 6.82 / 0.254

         F = 2.255 10³ N

     

c) It is requested to calculate the force of the ground on the man

            ∑ F = F_soil -W

           F_soil = F + W

           F_ {soil} = 2.255 103 + 84 9.8

           F_ {soil} = 3078 N

3 0
3 years ago
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