0.448 moles of ions will form when a 42.66-gram sample of magnesium chloride is dissolved in water (option A).
<h3>How to calculate number of moles?</h3>
According to this question, when magnesium chloride (MgCl2) dissolves in water, it dissociates into magnesium ions and chloride ions as follows:
MgCl2(aq) ⟶ Mg2+(aq) + Cl−(aq)
However, if a 42.66-gram sample of magnesium chloride is dissolved in water, this means that 42.66g/molecular mass of MgCl2 will be the number of moles of the ionic products.
molecular mass of MgCl2 = 95.3g/mol
moles = 42.66g ÷ 95.3g/mol = 0.448mol
Therefore, 0.448 moles of ions will form when a 42.66-gram sample of magnesium chloride is dissolved in water.
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Answer:
In the given figure, There are two atoms -
- Sodium ( Na )
- Chlorine ( Cl )
sodium has one electron in valence shell and to get noble gas configuration ( stability ) it need to donate the outer most electron.
whereas,
chlorine has 7 electrons in valence shell and to get noble gas configuration ( stability ) it need to get one more electron.
in this condition Na ( sodium ) donates it's outermost electron to Cl ( chlorine ) and both became stable.
but now sodium has more number of protons than the electrons hence it get positive (+) charge and chlorine has more electrons than the protons hence it get negative (-) charge
so, they get stick to each other by strong electrostatic force acting on the charged atoms and forms a salt " NaCl " ( sodium chloride ) .
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Answer:
2 moles of Substance B
Explanation:
Because 1 mole of any substance contains 6.02× 10²³ particles either atoms, molecules, ions or even electron(Avogardo Constant)
Therefore 12.04 × 10²³/ 6.02× 10²³ = 2 mole of Substance B
