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klemol [59]
2 years ago
5

Help pls I really need the answer I will brainlest​

Chemistry
2 answers:
zlopas [31]2 years ago
6 0

Explanation:

latitude at horizontal circular line and show anguler distance from the equator and Longitudes are semi-circular lines and show agular distance from the prime Meridian .

jeka57 [31]2 years ago
3 0

Answer:

Latitude: the angular distance of a place north or south of the earth's equator, or of a celestial object north or south of the celestial equator, usually expressed in degrees and minutes. (Left to right)

Longitude: the angular distance of a place east or west of the meridian at Greenwich, England, or west of the standard meridian of a celestial object, usually expressed in degrees and minutes. (Up and down)

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What is the application of chemistry​
vlabodo [156]

Answer:

Chemistry plays an important and useful role towards the development and growth of a number of industries. This includes industries like glass, cement, paper, textile, leather, dye etc. We also see huge applications of chemistry in industries like paints, pigments, petroleum, sugar, plastics, Pharmaceuticals.

3 0
3 years ago
202H8(9) + 7 O2(g) > 4CO2(g) + 6 H2O(9).
lilavasa [31]

since the concentration of Carbon Dioxide will increase, it would make Q > K, cause equilibrium to shift in the direction with less moles of gas to alleviate the extra pressure. In this case, the reaction will shift left because there are fewer moles of gas present.

4 0
2 years ago
What is the empirical formula for the compound P4O6??
777dan777 [17]
The empirical formula is P₂O₃
5 0
3 years ago
Please i need help really quickly on this. thank you​
prohojiy [21]

Answer:

the error could have been the fact that the unit for volume wasn't changed from cm³ to dm³

hence the calculation error

the solution to this would be first dividing the volume by 1000 to get that same amount in dm³ which is the standard unit to be used for volume-density calculations

6 0
3 years ago
A 150.0mL sample of an aqueous solution at 25C contains 15.2mg of an unknown nonelectrolyte compound. If the solution has an osm
Nookie1986 [14]

Answer:

MM = 225.11 g/mol

Explanation:

In this case, let's analyze the data.

We have a 15.2 mg of an unknown electrolyte in 150 mL of solution. The osmotic pressure is 8.44 Torr, and we want the molecular mass of the unknown.

The osmotic pressure can be calculated using the following expression:

π = CRT   (1)    

π: osmotic pressure (8.44 Torr * 1 atm / 760 Torr = 0.011 atm)

C: Concentration of the unknown in the solution

R: universal constant of gases (0.082 L atm / K mol)

T: temperature in Kelvin (25 + 273 = 298 K)

From this expression, we can either solve for C, and then use another expression to calculate the molecular mass, or we can just replace the expressions in the above formula, to get the direct molecular mass. In this case, we'll follow the second method.

Concentration or molarity of a substance can be calculated using:

C = moles / V  (2)

And moles can be calculated using this expression:

moles = m / MM   (3)

Replacing (3) in (2), and then in (1) we have:

C = m / MM * V

π = m * RT / MM * V   (4)

and now, we can solve for MM:

MM = mRT / π V  (5)

Now, we just need to replace the given data into the above expression to get the value of the molecular mass:

MM = (15.2 / 1000) * 0.082 * 298 / 0.011 * 0.150

<h2>MM = 225.11 g/mol</h2>

Hope this helps

3 0
3 years ago
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